In One Piece chapter 570, Whitebeard intercepts Kizaru and cuts him off before he ends his light journey. It is important to note that the photons of light were already beginning to move throughout all his body before him gets cutted.
- Kizaru's Head (90px): 0.4228m (His size is 3.02m)
- Particle of Light (28px): 0.131537m
- Panel: 203px
Now I need to find the distance from Whitebeard to Kizaru, it is impossible to know with complete certainty his position, so I will minimally consider that he is in the view of the screen in relation to Kizaru.
- 2atan (tan(70/2)*(90/203) = 0.414110121 Radians
- 0.414110121 ×180°/π = 23.726762187° Degrees
- Distance from Kizaru to Panel/Whitebeard: 1.0064m
- Time (1.0064/299,792,458) = 3.35698905e-9 (That's the time that WB moved)
Whitebeard had to move his arm 90 degrees to cut Kizaru, using his Murakumogiri.
- Whitebeard's size (150px) = 6.66m
- Whitebeard's arm (46px) = 2.04m
- Murakumogiri's size (169px) = 7.50m (But we will use only 1/3 of it due WB use only his blade to cut Kizaru) = 2.50m
- 90° Degrees = 1.5708 Radians
- 5.5464 (Distance + Murakumogiri and arm) x 1.5708 = 8.71228512m
Whitebeard's Speed (8.71228512/3.35698905e-9) = 2595267661.06m/s or 8.65c (FTL)
Good feat for daddy Whitebeard.