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Xanxussama1010

aka XANXUS

  • I live in Thailand
  • I was born on June 14
  • I am Male
  • Xanxussama1010

    Another calc for Majin Tantei Nougami Neuro. Let's start it.


    A bomber descended and clashed on the surface, which caused a large explosion.



    The scan above said that the bomber descended at Mach 2 and will clash in 3 seconds.

    Mach 2 is 686 m/s and with 3 seconds, Distance = 686 x 3 = 2,058m

    I will use this distance to find radius of the explosion.


    Low-End

    I assume that the red line is the distance.

    Red line: 551px = 2,058m

    Explosion's diameter: 443px = 1654.62m 827.31m, that's mean radius = 827.31m

    Over-pressure method : W = R^3*((27136*P + 8649)^(1/2)/13568 - 93/13568)^2

    W is yield in tons of TNT, R is the radius in meters, and P is the pressure of the shockwave in bars, the standard overpressure is 20 psi or 1.37895 bars.

    W = 827.31^3*((27136*1.3789…





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  • Xanxussama1010

    This is the recalc of this calc. I see that some of the detail can be updated. So I redo it.


    A girl use Rexblt spell, which summons a storm that creates a pretty hefty lightning bolt


    First pic

    I assume the girl's height is 177cm like the old calc.

    girl: 190px = 1.77m

    Distance between girl and dragon: 610px = 5.68m

    Seccnd pic

    girl: 92px = 1.77m

    Bolt's diameter: 70px

    Screen's height: 716px

    I'll find the distance of the girl with angular size here. Use 2atan(tan(70/2)*(object size in pixels/screen height in pixels)) to get degrees

    2atan(tan(70/2)*(92/716)) = 6.96787367 degree

    Input degree and her height to calculator. distance = 14.537m

    That's mean distance for dragon should be 14.537 + 5.68 = 20.217m. I'll use this to find value of bolt's diameter

    Time fo…



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  • Xanxussama1010

    Seeing that we currently accept crushing feat as Lifting Strength. So I want to try this one.


    An antagonist casually bear hugs a very thick tree and breaks it in half.

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  • Xanxussama1010

    Calc requested by Sorvoe551. Let's see how should I do about this.


    Tierra made self-destruction and Sasazuka jumped away from it. I'll find the speed of Sasazuka to did that.


    1st pic

    Neuro's face: 172px = 26.72cm

    Tierra's head: 184px = 28.58cm

    2nd pic

    Tierra's head: 58px = 28.58cm

    Distance between Tierra's neck and his left body: 104px = 51.25cm or 0.5125m

    The feat shows that Neuro coated his head and neck. Tha's mean he should be able to reach him before the explosion reach Tierra's neck

    The explosion can reach 8.009m in 0.00607s from the calculation above.

    Then, timeframe for explosion to reach Tierra's neck = 0.00607 / 8.009 x 0.5125 = 0.00038842239s

    Neuro reached him with this timeframe.

    So, Neuro's speed = 8.009 / 0.00038842239 = 20,619.30 m/s or Ma…



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  • Xanxussama1010

    Calc requested by YukaSama4. Let's try it.


    Fon use his ultimate attack against Xanxus and Squalo. Which he claimed that his move will happen in microns of seconds.


    First Pic

    Hibari: 348px = 169cm

    Hibari's head: 48px = 23.31cm

    Second Pic

    Hibari's head: 94px = 23.31cm Fon's head: 78px = 19.34cm

    Third pic

    Xanxus: 438px = 188cm

    Xanxus' head: 36px = 15.45cm

    Forth pic

    Xanxus' head: 97px = 15.45cm

    Fon's head: 23px = 19.34cm

    Screen's height: 603px

    Find distance between Xanxus and Fon with Angular Size

    Distance for Xanxus

    Use 2atan(tan(70/2)*(object size in pixels/screen height in pixels)) to get degrees

    2atan(tan(70/2)*(97/603)) = 8.71719423 degree

    Input degree and size of Xanxus' head in calculator. Distance = 101.35cm

    Distance for Fon

    2atan(tan(70/2)*(23/603)) = 2.…



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