Weiss is 1.6 m tall
1.6 / 45 = .03555555555 m/px
.03555555555 x 269 = 9.56444444444 m
9.56444444444 / 7 = 1.36634920635 m/px
1.36634920635 x 57 = 77.8819047619 m
The ship is below the peak of the cliff, so:
77.8819047619 / 34 = 2.2906442577 m/px
2.2906442577 x 146 = 334.434061625 m
Gonna have to angsize these...
Going from left to right:
Object size = 2*tan(70deg/2) * distance from point of view to object * object height in pixels / panel height in pixels
Object size = 2*tan(70deg/2) * 334.434061625 * 57 / 1200 = 22.2464588435 m / 2 = 11.1232294217 m
Object size = 2*tan(70deg/2) * 334.434061625 * 26 / 1200 = 22.2464588435 m / 2 = 10.1475075426 m
Using this calculator gives us a volume of 2504.09260 m^3
Object size = 2*tan(70deg/2) * 334.434061625 * 78 / 1200 = 22.2464588435 m / 2 = 30.4425226279 m
Object size = 2*tan(70deg/2) * 334.434061625 * 70 / 1200 = 22.2464588435 m / 2 = 27.3202126148 m
Object size = 2*tan(70deg/2) * 334.434061625 * 56 / 1200 = 22.2464588435 m / 2 = 21.8561700918 m
Object size = 2*tan(70deg/2) * 334.434061625 * 53 / 1200 = 22.2464588435 m / 2 = 20.6853038369 m
Using this calculator gives us a volume of 15264.601517 m^3
Object size = 2*tan(70deg/2) * 334.434061625 * 55 / 1200 = 22.2464588435 m / 2 = 21.4658813402 m
Object size = 2*tan(70deg/2) * 334.434061625 * 51 / 1200 = 22.2464588435 m / 2 = 19.9047263336 m
Using this calculator gives us a volume of 4669.2701476839 m^3
2504.09260 + 15264.601517 + 4669.2701476839 = 22437.9642647 m^3 = 22437964264.7 cm^3
Its very clearly just normal fragmentation so:
22437964264.7 x 8 = 179503714118
As this was done by three fireballs, divide the result by three = 59834571372.5 Joules, City Block level
Recalc (ACCEPTED VALUE)[]
Weiss is 1.6 m tall
1.6 / 45 = .03555555555 m/px
.03555555555 x 269 = 9.56444444444 m
9.56444444444 / 196 = .04879818594 m/px
.04879818594 x 125 = 6.09977324263 m
6.09977324263 / 46 = .13260376614 m/px
.13260376614 x 442 = 58.6108646357 m
58.6108646357 / 266 = .22034159637 m/px
.22034159637 x 710 = 156.442533426 m
156.442533426 / 537 = .29132687788 m/px
And now for the craters, going from left to right:
57 x .29132687788 = 16.6056320396 m
32 x .29132687788 = 9.32246009216 m
26 x .29132687788 = 7.5744988251 m
56 x .29132687788 = 16.3143051613 m
Using this calculator gives us a volume of 1602.0019844 m^3
78 x .29132687788 = 22.7234964746 m
53 x .29132687788 = 15.4403245276 m
70 x .29132687788 = 20.3928814516 m
Gives us a volume of 6348.469402 m^3
51 x .29132687788 = 14.8576707719 m
26 x .29132687788 = 7.57449882488 m
70 x .29132687788 = 16.0229782834 m
Gives us a volume of 2931.9267086 m^3
1602.0019844 + 6348.469402 + 2931.9267086 = 10882.398095 m^3 = 10882398095 cm^3
Its very clearly just normal fragmentation so:
10882398095 x 8 = 87059184760 Joules, 20.8 Tons of TNT, City Block level
As this was done by three fireballs, divide the result by three = 29019728253.3 Joules, 6.935 Tons of TNT, Large Building level+
Weiss used 8 fireballs in total from this one canister of Fire Dust, giving the total yield of on canister 232157826026 joules, 55.487 Tons of TNT, City Block level+
The Queen Lancer tanked a minimum of canisters of Fire Dust being detonated in its face at once, or 5 1.1607891e+12 joules, 277.435 Tons of TNT, Multi-City Block level