I've calculated this feat before, however, the calculation had wrong assumptions, so, decide to bring another method, come on.
First of all, I will find the time and, for that, we will use the three scans posted above. As we see, the moment one of Nariki's mercenaries fires, Iaian starts to move and realizes that the empty cartridges that came out of the weapon are frozen in the air, Iaian travels the entire distance between them and hits him, this with the frozen cartridges Up in the air. Here we will find the speed that the cartridge would fall to the ground and we will use the snail's time, because, as we see, the cartridges are frozen in the air during the entire movement of Iaian.
Velocity formula s/t only works for linear movement. You need to either use double the distance ( 2 * 1.80 / 0.6058 ) or multiply this timeframe by the acceleration (9.80665 * 0.6058) so 5.9425 m/s. Using the snail speed to find the real time:
- T = 0.001 / 5.9425
- T = 0.0001682 seconds
- Dude = 71px | 1.80 meters
Screen = 231px
- D = 1.80 * 231 /[71 * 2 * tan (70deg / 2)]
- D = 4.18185874087 meters
That was the initial distance between them, however, Iaian moved forward, cut the four bullets and even cut the mercenary Nariki who shot him.
Iaian is 1.78 meters, his arm is 0.6764 meters. The Katana has an average of 0.75 meters.
- Arm + Sword = 1.4264 meters
Considering that, for each bullet, he moved his arm 90 degrees, which would give 2.2405 meters for each shift, as there were 4 bullets, that is 8.962 meters.
However, he also hit the Mercenario 4 times, so that would be another 6.2405 meters.
- M = 4.1818587 + (8.962 * 2)
- M = 22.1 meters
- V = 22.1 / 0.0001682
- V = 131391.2 m/s
- Iaian moving very fast = 131391.2 m/s, or Mach 386 (Massively Hypersonic)