25,496 Pages

## Calc

First we need to find the size of Black Sperm.

Atomic Samurai = 352px | 1.77 meters
Black Sperm = 220px | 1.10 meters

Body volume of an average 1.7 m tall person to approximately 0.0693 m³.

BS is 1.1 m tall, therefore his body volume is:

0.0693 /(1.7 / 1.1)³ = 0.01877 m³

A particle is about 60 micrometers in diameter (6e-5 meters).
The volume of a single particle:

• V = 4/3 * Pi * 3e-5³
• V = 1.131e-13 m³

With this, we can find out how many particles the body has been reduced.

• Q.p = 0.01877 / 1.131e-13
• Q.p = 1.659593e+11

To isolate each particle, a movement around it is required, which can be given by:

• C = 4 * 6e-5
• C = 1.884e-4 meters

Therefore, the total movement to completely reduce the body to particles is:

• D = 1.884e-4 * 1.659593e+11
• D = 31266732.12 meters

I can count at least 11 bodies, this gives: 343934053.32 meters

### Time

Atomic Samurai is 1.77 meters, so head is: 0.2301 meters

Head = 26px | 0.2301 meters
Hole = 157px | 1.38945 meters

Hole = 22px | 1.38945 meters
Panel = 1135px

• D = 1.38945 * 1135 / [22 * 2 * tan (70deg / 2)]
• D = 51.186 meters

Using freefall to find the time:

D = G * T² /2
At where:
D = Distance
G = Gravitational acceleration
T = Time

• 51.186 = 9.807 * T² /2
• 9,807 * T² /2 = 51.186
• T² * 4.9035 = 51.186
• T² = 51.186 / 4.9035
• T² = 10.438
• T = 3.23 seconds

### Velocity

• V = 343934053.32 / 3.23
• V = 106481131.059 m / s, or Mach 313179.79

## Result

• Atomic swing speed = 0.35c (Relativistic)
Community content is available under CC-BY-SA unless otherwise noted.