Introduction[]
In One Punch Man Chapter 164, Garou pushes Saitama against the surface hard enough to displace the Earth's crust. I will be calculating the force needed to perform this feat.
Calculation[]
Lithosphere = 100 km
Displaced Height = 404.8 km or 404800 m
Displaced Width = 454.5 km
Displaced Base Radius = 454.5/2 = 227.25 km or 227250 m
We put these values on this Paraboloid Calculator to get the volume of the displacement.
Volume = 32837354.74042 km^3 or 32837354740420000 m^3
The lithosphere has a density of 2700 kg/m^3.
Displaced Mass = 32837354740420000 x 2700 = 88660857799134000000 Kilograms
Now we can find the force behind this push. We're going to assume Garou pushed the crust in 5 seconds.
Distance = 404800 m
Timeframe = 5 seconds
Speed = 404800/5 = 80960 m/s
Acceleration = 32384 m/s^2
Force = 88660857799134000000 x 32384 = 2871193218967155456000000 Newtons of Force
Kinetic Energy
Yield = 0.5*88660857799134000000*80960^2 = 290564753759476132147200000000 Joules
Final Tally[]
Garou's Lifting Strength = 292780227597301380000 Tons of Force (Class Z)
Garou Pushes The Surface = 69.44 Exatons of TNT (Moon level)