Introduction
We want to calculate the value required to destroy all regular matter (in other words, excluding antimatter, dark matter, dark energy and exotic matter) of the observable universe. To do this, we will be assuming a celestial object at the edge of the observable universe, and calculating the energy of a center-originating omni-directional blast, required to destroy said celestial object.
Energy Formulas used:
- GBE = 0.6 x G(M^2)/R
- G = Universal gravitational constant
- M is mass of the celestial object in kilograms
- R is radius of object in metres
- Energy to destroy using a center-originating omni-directional blast = GBE x 4(π)(A/R)2
- R is radius of object to be destroyed
- A is distance from center point of blast
Low End
Assuming Sun at the edge of the observable universe.
Mass = 1.9888 x 1030 kg
Radius = 6.955 x 108 m
GBE = 0.6 x G(M2)/R = 0.6 x (6.67 x 10-11) x (1.9888x1030)2/(6.955x108) = 2.2759x1041 J
Energy needed to destroy it (located at edge of observable universe) from center-originating omni-directional explosion, from center of universe = GBE x 4(π)(A/R)2
=> (2.2759x1041) x 4(π) x ((46.6x109)(9.46x1015)/(6.955x108))2 = 1.149x1078 J
High End
Assuming neutron star (this) at the edge of the observable universe.
Mass = 2.10 solar masses = 2.01 x 1.9888 x 10^30 kg = 3.997488x10^30 kg
Radius = 13 km (mean radius) = 13000 m
GBE = 0.6 x G(M2)/R = 0.6 x (6.67 x 10-11) x (3.997488x1030)2/(13000) = 4.92x1046 J
Energy needed to destroy it (located at edge of observable universe) from center-originating omni-directional explosion, from center of universe = GBE x 4(π)(A/R)2
=> (4.92x1046) x 4(π) x ((46.6x109)(9.46x1015)/(13000))2 = 7.11x1092 J
Conclusion
Energy required to destroy the observable universe:
- Low end: 1.149x1078 Joules
- High end: 7.11x1092 Joules
Note: This is not the value required for Universe level. This is an intermediate value, an anecdote, for those interested.