Introduction[]
Illiminating an entire universe/absorbing the light of the universe is a feat that lately showed up in various medias and in the same way, so I'll make a blog for these characters. Credit to Matthew Schroeder for the original calc
Calculation[]
I will use the apparent magnitude of Sirius, the brightest star in the Night-Sky.
Using this formula:
https://wikimedia.org/api/rest_v1/media/math/render/svg/fa13db5bce810b9d7667302abaefae0e83742cab
- M(star) is the apparent magnitude of the light source
- m= is the apparent magnitude of the sun (-26.73)
- L(star) is the Luminosity
- L= Luminosity of the sun (3.486*10^26)
- d= Distance to the sun from earth (0.000004731537734207877 parsecs)
- d(star)= distance to the light source
or: M= -26.73 - 2.5log ((L/3.846*10^26)(146000000000/d)^2)
- M is the apparent magnitude
- L is the luminosity in L
- d is the distance from the source of light (in meters)
The ristance is 46.5 billion light-years (4.399e26 m), so let's calc
-1.47 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(4.399e26))^2)
L = ~2.747966869e47 W, or 2.747966869e47 Joules for second
For absorbtion, we'll take just 1 second
Result[]
Illuminating/absorbing the light of an universe = 2.747966869e47 Joules or 2.75 KiloFOE (Solar System level)