Thor moves Nidavellir's ring

Feat.

First I need to explain this feat a little bit.

Firstly, Thor slung Rocket's spacecraft thousand of metres away, then placed his arm and feet onto the ground tearing up massive amounts of metal. He then manages to stop at the edge and breaks the ice to reignite the star.

Credit to [https://comicvine.gamespot.com/forums/gen-discussion-1/complete-breakdown-of-mcu-thors-star-forge-feat-1948194/ this guy] on Comic Vine for explaining this feat.

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To anchor himself to the Rings, Thor has to apply an equal amount of force as the Pod in the opposite direction to remain in a constant position so that the Rings are the only objects that can give way. If you're going to talk about physics then talk about it correctly. It is LITERALLY just tug of war physics. One side is pulling (Pod) and the other side is trying not to get pulled (Thor). If they apply equal force in opposite directions then they remain stationary. Unless the ground beneath them (Thor's anchor) gives way (the Rings) thus allowing motion can occur. To simplify further: Tug of War where one side has solid ground (Pod) and the other has mud for ground (Thor). Newton's Second Law people. The Pod and Thor applied equal force. The Rings gave way. In other words, Thor applied a force equal to that what was necassary to move the rings.

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Firstly, Thor has to apply equal force to him throwing the pod plus Rocket pulling the pod, and still manages to stop at the edge. It's basically just tug-of-war physics where one side has solid ground while the other doesn't. And the Pod and Thor applied equal force, but the Rings gave way. Therefore, Thor applied a force to what was necessary ro move the rings.

Some people say that Thor did it in space, but firstly these rings have gravity as we see Thor fall from the ship to the ring, and secondly being in space would actually make the feat more impressive, as Thor held his feet on the ground without gravity.

And those rings are MASSIVE. They easily dwarf Iris which makes Rocket's ship look minuscule in comparison.

Speed

Media:flatamuseddamselfly.mp4

The width of the rings is 7710 m according to this calculation which pixel scales the size of the giant ring.

I used the third ring in the first shot (second ring in the second shot) for scaling.

Time passed = 5.82-2.38 seconds = 3.44 seconds

Width of ring = 22 px or 7710 m

Distance moved = around 9 px or 3154.09 m

Speed = 3154.09/3.44 = 916.89 m/s

Word of God

Greg Steele, the VFX supervisor of the company that did the scene stated that the ring is the size of a small moon.

https://www.awn.com/vfxworld/how-method-studios-crafted-rocket-20-avengers-infinity-war

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It’s this whole Rube Goldberg-type of machine that we had to get going. It had to be extremely high resolution and working either a foot away from the surface to miles and miles away. It’s the size of a small moon."

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According to our Lifting Strength page, a small moon is Class P, or at least 10^15 kg.

0.5*1e15*916.89^2 = 4.2034363605e20 Joules, Large Island level

Pixel Scaling

This guy on YouTube calculated the size of the giant ring by comparing it to the neutron star. He calculates it to be 4.0471893*10^16 kg (assuming density of steel) and 1.03019364e17 (assuming density of tungsten).

Basically he pixel scaled the ring by comparing it to the neutron star and used formulas to find it's height, width and length. He even accounted for things like spacing between rings and the hollowness. And tbh I think he low-balled it by assuming 90% hollowness and assuming the space in between the ring is half of the ring.

I'll use the low-end.

0.5*4.0471893e16*916.89^2 = 1.7012102661446543e22 Joules, Small Country level+

Low-ball

For some people who said Thor only moved the rings a little bit and they moved by themselves, let's assume they moved 1 pixel per second when Thor started it, or 385.5 m/s.

0.5*4.0471893e16*385.5^2 = 3.007269068351625e21 Joules, Large Island leel+