VS Battles Wiki

We have moved to a new external forum hosted at https://vsbattles.com

For information regarding the procedure that needs to be exactly followed to register there, please click here.

READ MORE

VS Battles Wiki
Advertisement
VS Battles Wiki

Apparently Endless Mike's calc is wrong, according to this CRT.

Iron Man did not push the rotors at the speed they originally move at. That's an idiotic assumption to make.

"A better method would be to calculate the power output that would be required to keep the Heli-carrier in the air, then using that to determine Ironman's power output."

Blah blah blah blah blah. You know what? Instead of doing some shitty calculations how Iron Man kept the helicarrier flying, why don't we just make things simple and calculate the KE of Iron Man pushing that stuff?

Original calc.

Seems that he also calculated the speed of Iron Man.

I'm guessing you probably also wanted to know how fast he was going. Back to Rowvid then.

This time we're looking at two screencaps 1 frame apart from each other. On the first one I measured the angle to where he is on the second:



From my previous scaling, rotor diameter = 45.11446033 m
Radius of Iron Man's path: 18.30516698 m

Measuring the angle in GIMP, I get 95.48 degrees.

180/95.48 = 1.885211563

(18.30516698 * pi)/1.885211563 = 30.50446923 m. At 25 frames/second, that's 762.6117306 m/s or Mach 2.241064182.

~ Endless Mike

This is the amount of mass Iron Man moved, or 5 421 600 kg.

762.6117306^2*5421600*0.5 = 1.5765379872893691e12 Joules, or Multi-City Block level


Edit: Recently noticed this comment, makes a good point.

Problem 1. The stated mass assumes it's made out of titatnium when aluminium seems far more reasonable. (after all they are probably going to want to cut down on the weight.) Aluminium has a density of 2700kg/m^3 rather then Titaniums 4500kg/m^3 Also one thing that's important to note is that the parts of the rotor that are near the edges will be going faster the the parts in the middle, this reduces the kinetic energy. The kinetic energy per mass of each part of the rotor is therfore pro-portional to the square of the distance that part of the rotot is from the center. And the integral of x^2 = 1/3*x^3. This reduce the energy by a factor of 3. 60.24*2700*20=3261600kg. 3261600*762.6117306^2/2/3=316,145,067,836J=75.56tons. City block+

So slightly less than before.

Advertisement