Credit
Credit to Darkanine for making the OG calc
Timespan Math
This is a long one, so bear with me.
First, let's find out a Mid-Lowball time span instead of the Lowball in the original calc.
37 (Broly's Age) * 12 (Number of Months Per Year) * 31 (Highest amount of Days per month (Low-Ball)) * 16 (Number of Hours per day, assuming Broly gets 8 hours of sleep + Eating, (Mid-Ball)) * 3600 (Amount of seconds in a hour) = 792806400
Math (Lowball, No Longer Usable)
This part is assuming the Milky Way Galaxy is 250,000 Lightyears in circumference.
250000 LY / 792806400 seconds (Timespan) = 0.000315335496787x Lightyears per second
0.000315335496787 * 9.4605284 * 10^15 (Meters per LY) = 2.9832404229 * 10^12 meters per second
2.9832404229×10^12 / 2.998 * 10^8 (Speed of Light) = 9950.76858873 x FTL
Math (Highball, No Longer Usable)
This part assumes the Milky Way Galaxy is 300,000 Lightyears in circumference.
300000 LY / 792806400 seconds (Timespan) = 0.000378402596145x Lightyears per second
0.000378402596145 * 9.4605284 * 10^15 (Meters per LY) =3.5798885075 * 10^12 meters per second
3.5798885075 * 10^12 / 2.998 * 10^8 (Speed of Light) = 11940.9223065x FTL
Original Results (No Longer Usable)
Lowball: MFTL+ (9950.76858873 x FTL)
Highball: MFTL+ (11940.9223065x FTL)
Note
This is not counting the fact that he had completely destroyed starting from the middle and had gone back several times during his rampage to areas he had destroyed to destroy even more solar systems near there. All in all, this is still a massive lowball.
Math (Legendary Edition)
Summary: I'm going to try to calc the distance Broly travels while he destroys the galaxy in its entirety based on the area he destroys every couple of frames, in order to deal with the dilemma stated in my note.
First, let's pixel scale the galaxy's diameter.
I got 419 pixels = Diameter of Galaxy (100000 lightyears assuming its as big as the Milky Way galaxy, which is rather fair considering how big some other galaxies can get.)
The First
First Screenshot (10 Seconds In)
Broly apparently skipped a few solar systems when he first began, so let's calc from the farthest two.
Y Distance: 58 px
y/58 = 100000/419
13842.4821002 LY
X Distance: 62 px
x/62 = 100000/419
14797.1360382 LY
Z Distance:
13842.4821002^2 + 14797.1360382^2 = √410569545.627
20262.5157773 LY
The Second
Second Screenshot (Still 10 Seconds In)
Y Distance: 120 px
y/120 = 100000/419
28639.6181384 LY
X Distance:87 px
x/87 = 100000/419
20763.7231504 LY
Z Distance.
20763.7231504^2 + 28639.6181384^2 = √1.2513599262 * 10^9
35374.566092 LY
The Third
Third Screenshot (11 Seconds In)
Y Distance: 209 px
y/209 = 100000/419
49880.6682578 LY X Distance: 149 px
x/149 = 100000/419
35560.8591885 LY
Z Distance.
35560.8591885^2 + 49880.6682578^2 = √3.7526557721 * 10^9
61258.9240201 LY
The Fourth
Fourth Screenshot (Still 11 Seconds In)
Y Distance: 90 px
y/90 = 100000/419
21479.7136038 LY
X Distance: 190 px
x/190 = 100000/419
45346.0620525 LY
Z Distance.
45346.0620525^2 + 21479.7136038^2 = √2.5176434402 * 10^9
50176.1242046 LY
Current Total LY: 167072.130094
Math (Legendary 2 Edition)
Timespan for Last Frame of Destruction Math:
Frames per second: 25f/s
792806400 seconds of Destruction is presented in 5 seconds (125 frames)
792806400 / 125 = 6342451.2
250000 / 6342451.2 = 0.0394169370984 LY / second
0.0394169370984 * (9.4605284 * 10^15) = 3.7290505286 * 10^14
(3.7290505286 * 10^14) / (2.998 * 10^8) = 1243846.07358x FTL
Result: 1,243,846.07358x FTL
Note #2
In a perfect World, it would have been possible to have done this frame by frame.
But that's at least 100 frames to check and calc, which is basically impossible unless I did it for my entire summer break and then some.