Introduction[]
I'm going to calculate the following things:
- Dave breaking Derse's chain.
- John drills a hole in the battlefield.
- The meteor that fell in Jade's island.
First Calc[]
Derse's Moon mass[]
First, I am going to determine it's size by comparing it to Derse itself.
At most, Derse is comparable in size to a land. And acording to the commentary of Homestuck's Book 3:
- "...These "lands," of course, are fairly small planets. Hard to say how big exactly. I don't think I ever really did any due diligence on the cosmological scale of these bodies. They're big enough to explore and get lost in but not so huge as to be hopelessly unchartable. I guess I always pictured them being like a small state in the US. Like if Rhode Island or Connecticut were wrapped around a sphere."
So sphere calculator for radius:
Using Rhode Island: 15807.4 m
Using Connecticut: 33800.8 m
Derse's moon radius (Using Rhode Island): (15807.4/265)*78 = 4652.744150943 meters
Derse's moon radius (Using Connecticut): (33800.8/265)*78 = 9948.914716981 meters
Now, Derse's Moon seems to have the same gravity as Earth (Do not ask me how that works), so:
Using Rhode Island:
g = G * M / r²
9.81 = (6.67 * 10⁻¹¹) * M / 4652.744150943²
(9.81*4652.744150943²)/(6.67 * 10⁻¹¹) = 3.1839154e+18kg
Using Connecticut:
g = G * M / r²
9.81 = (6.67 * 10⁻¹¹) * M / 9948.914716981²
(9.81*9948.914716981²)/(6.67 * 10⁻¹¹) = 1.4557761e+19kg
Okay, after certain comment by Podonklos, I'm just going to use earth's density (5.51 g/cm³). So handy spere calculator tells us:
Using Rhode Island: 9.11636148e+16 kg
Using Connecticut: 8.91294335e+17 kg
Derse's moon speed[]
Given that the moon begins to drift away as soon as Dave breaks the chain.
(Yes, I am well aware that besides Doc Scratch and Andrew Hussie no character has canon size, this is an approximation)
Andrew's height: 6 feet = 1.8288 meters
Dave's height: (1.8288/412)*235 = 1.043126214 meters
Distance: (1.043126214/55)*209 = 3.963879613 meters
Timeframe: 0.30 seconds
Speed: 3.963879613*(1/0.30) = 13.212932043 m/s
Putting this into the calculator gives us 7.95774e+18 joules for Rhode Island (High 7-A, Large Mountain level) and 7.78018e+19 joules for Connecticut (6-C, Island level). Given that the chain can take this much force, then breaking it must take a similar or stronger force.
Not sure which will be accepted, I'm fine with both.
Second Calc[]
Hole's Volume[]
Hole's Radius: ((1274200/350)*35/2) = 63710 meters
The hole reaches the center of the Battlefield, so the dept is 637100 meters
Out of sheer laziness, I will use a cillinder calculator, that gives us 8.127321802631421e+21 cm³
There are not leftovers, so pulverization.
8.127321802631421e+21*214.35 = 1.742091428e+24 (High 6-B, Large Country level)
Third Calc[]
Meteorite's mass[]
First, size:
Good thing the meteorite is roughly spherical
Meteorite's radius: ((1274200/350)*43)/2 = 78272.285714286 meters
Meteors seems to have an average density of 3.4 g/cm³. So...
Meteor's mass : [(4/3)*π*78272.285714286³]⋅3.4 = 6.82954192e+18 kg
Now, for speed. Sadly, I couldn't get a HQ gif, but it wont change the result very much:
Distance: ((1274200/237)*16)-((1274200/237)*10) = 32258.227848101 meters
Timeframe: 2.08 seconds
Speed: 32258.227848101/(1÷2.08) = 67097.11392405 m/s
Putting this into the kinetic energy calculator gives us 1.53734e+28 joules (High 6-A, Multi-Continent level)
Final results[]
Breaking Derse's chain: 7.95774e+18 joules (High 7-A, Large Mountain level) to 7.78018e+19 joules for Connecticut (6-C, Island level)
John drills a hole in the Battlefield: 1.742091428e+24 joules (High 6-B, Large Country level)
A meteor falls in Jade's Island: 1.53734e+28 joules (High 6-A, Multi-Continent level)
Note: I am unable to comment in blogs for some reason. I might use a sockpuppet if I need to talk.