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I'm recalcing this because of 2 things.

  1. I found out that the circle above the palace isn't to scale, since that was another attack.
  2. The KE for the cut should actually be 1/2, instead of 1/12

Here's the pixel-scaled image.

The Cut[]

The distance cloud is from the ground is 206 pixels. I'll use an average of 4.5km distance, since Nimbo clouds are only 3 kms in like polar regions only, and are only higher from there. I'll use the ones from temperate regions, which are from 2km to 7km.

Size of each pixel = 4500/206

Size of each pixel = 21.8446601 meters

The length of the cut = 619 x size of each pixel

The length of the cut = 13,521.84... meters

The width = 83 x size of each pixel

The width = 1,813.106796 meters.

Height = I'll assume 4000 meters, since the clouds seem absolutely dense as fuck.

The volume (Rectangular Prism formula) = 98100000000 m3

Where he began the cut[]

Since the dude who did all of this is in the middle of the palace, I'll just take the radius of the dispersion of the cloud above the palace.

Diameter = 9,567.961165, divide by 2 to get radius, and we get 4,783.98058 meters. He began the cut from there.

The speed[]

I'll just take the radius of the dispersion of the cloud above the palace, and the length of the cut it made to the clouds. then divide by the time.

Distance = 4,783.98058 + 13,521.84 = 18,305.82058 meters

We already have an accepted end, which is 1 seconds.

V = 18,305.82058/1 = 18,305.82058 m/s

Kinetic Energy[]

So first, we need to get the mass of the clouds.

Mass = 98100000000 * 1.003 = 98,394,300,000 kg.

Now, for the most important part, Kinetic Energy. I'll use the three ends of the speeds we got.

KE = 1/2 x 98,394,300,000 x (18305.8)^2 = 1.6486079e+19 joules, or 3.940267 Gigatons (High 7-A+)

Results[]

3.940267 Gigatons of TNT, Large Mountain level+ (High 7-A+)

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