Nuclear Missile:[]
During chapter 102 America launches 567 Nuclear missiles at Korea. The South Korean president questions if they are going to remove Korea from the map. In chapter 107 Jaesan Jeon using his alchemy transforms all the 567 nuclear missiles into one large one. We don't know how powerful the nuclear missiles are, so for this calc I will be using 4 out possible options. Using the information provided from the app Nukemap and converting the yield into joules, I will be using:
1) "Castle Bravo" Largest US Bomb Tested (15 megatons)= 6.276e+16 Joules.
2) "Tsar Bomba" Largest USSR Bomb Tested (50 megatons)= 2.092e+17 Joules.
3) "Tsar Bomba" Largest USSR Bomb Designed (100 megatons)= 4.184e+17 Joules.
Now time to multiple with the number of missiles:
1) 6.276e+16x567= 3.558492e+19 6-C Island (Accepted)
2) 2.092e+17x567= 1.186164e+20 6-C Island
3) 4.184e+17x567=2.372328e+20 6-C Island
Using this method, we can calculate the massive missile being Island Level.
Meteor Summon:[]
In chapter 107 , Jaesan Jeon also summons a massive meteor down upon the giant nuclear missile to use it as a hammer to the nail. To find the size of the meteor, we first need to find the angel's (giant white dude) head as a reference.
Looking at the head we can see that the angels dwarf humans. Using Mandeok Sang (Since Jeon is a giant among humans) we can scale the height of the head. The angel's head measures to 597px. The average male height in South Korea is 175.26cm.
Mandeoks head and torso= 55px
Mandeoks thigh= 17.6215141166px
Mandeoks calf= 46px
Overall Mandeoks height is: 55+17.62115141166+46= 118.621151412px
Now that we know that we can scale it to the head.
597/118.621151412= 5.03282924583
5.03282924583x175.26= 882.053653624cm (8.82m).
Now that is done and out of the way. Now we can move on to the big one, the meteor.
There as two images of the massive meteor. The second image I am unable to pixel scale with my available tools. However, the two images don't really vary or contradict each other, even both being ellipsoids. The second one is basically a further back shot of the meteor showing more of it. I'll leave up to you guys.
The head of the angel come out to be 3px (8.82m).
The measurements for the meteor come out to be 1100 px (B semi-axis) and 907px (A and C semi-axis). The following bit is for the next part. It askes for the radius.
1100/3= 366.666666667
366.666666667x8.82= 3234
3234/2= 1617m (B semi-axis)
907/3= 48.4666666667
302.333333333x8.82= 2666.58
2666.58/2= 1333.29m (A and C semi-axis)
Now we just have to figure out the mass for the meteor. According to this peer-review journal, a meteor can have a density between 3-3.7 g/cm^3. For this calculation, I will be using 3, 3.35 and 3.7 g/cm^3. Using this calculator and the values I've calculated, the mass of the meteor comes out to be:
3g/cm^3= 3.61217787E+13 kg
3.35g/cm^3= 4.03359862E+13 kg
3.7g/cm^3= 4.45501937E+13 kg
Almost there, the force. For this part, I will be using the KE. I will be using the dark flight speed for the meteor, as which is 4km/sec (4000 m/sec). As mentioned by AlexSoloVaAlFuturo, " the thing doesn't have friction that generates the fire from entering the atmosphere".
Low ball:
0.5x3.61217787E+13x4000= 7.2243557e+16 7-B City
Mid ball:
0.5x4.03359862E+13x4000= 8.0671972e+16 7-B City
High ball:
0.5x4.45501937E+13x4000= 8.9100387e+16 7-B City
Now the big finish. The meteor was down in combination with the giant nuclear missile feat, hence the hammer to the nail. Now we just add the two results together.
Low ball:
3.558492e+19+7.2243557e+16= 3.5657164e+19 6-C Island
Mid ball:
3.558492e+19+8.0671972e+16= 3.5665592e+19 6-C Island
High ball:
3.558492e+19+8.9100387e+16= 3.567402e+19 6-C Island
Killing Hundreds of Angels:[]
When Mori jin's Yeoui Extended for the first time in chapter 108, he entended up killing hundreds of angels at once, causing them to explode. However, this is a low ball as the angels weren't limited into the one area in the scans below but were also in space. This calculation is only counting the ones shown in the scans.
Scan 1 shows the angels after the Yeoui expansion exploding, while the second shows them before exploding. Between the two scans, I was able to count 208 (Scan 1) and 218 (scan 2). I will be using 208 as a low ball and 218 as a high ball.
Low ball:
3.6292699e+19x208= 7.5488814e+21 Low 6-B Small Country
3.6375273e+19x208= 7.5660568e+21 Low 6-B Small Country
3.6457847e+19x208= 7.5832322e+21 Low 6-B Small Country
High Ball:
3.6292699e+19x218= 7.9118084e+21 Low 6-B Small Country
3.6375273e+19x218= 7.9298095e+21 Low 6-B Small Country
3.6457847e+19x218= 7.9478106e+21 Low 6-B Small Country
Piercing The Moon:[]
When Mori Used his Yeoui for the first time in chapter 108, it casually pierced and left a hole in the moon. First we need to find the size of the hole what was left in the moon. Using these two scans we can determine their size.
The measurements for scan 1 are that the green line is 446px and the yellow line is 20 px. The moon diameter is 3474.2 km (3474200 m). We need to find the Yeuoi's base diameter.
20/446= 0.04484304932
0.04484304932x100= 4.48430493274%
4.48430493274% of 3474200m =155793.721973 m
Scans 2 measurements come have the diameter of the moon at 864px and the Yeoui's base at 94px.
94/864= 0.10879629629
0.10879629629x100= 10.8796296296%
10.8796296296% of 3474200= 377980.092592 m
Now using these sizes we can determine the volume of the hole left in the moon. Using this calculator we can determine the volume.
Scan 1= 6.6228452e+22
Scan 2= 3.8983655e+23
Now for the final step. I will be using values of pulverization and vaporization.
Scan 1:
6.6228452e+22x214.35= 1.4196069e+25 6-A Continental
6.6228452e+22x25700= 1.7020712e+27 High 6-A Multi-Continental
Scan 2:
3.8983655e+23x214.35= 8.3561464e+25 High 6-A Multi-Continental
3.8983655e+23x25700= 1.0018799e+28 High 6-A Multi-Continental
Another scan that can be used for this feat is the one from the promotional animated intro for the series. The measurements for the moon come out to be 505x517px. The holes diameter measures to be 74px.
74/505= 0.14653465346
0.14653465346x100= 14.6534653465
14.6534653465% of 3474200= 509090.693068 m
74/517= 0.14313346228
0.14313346228x100= 14.3133462282
14.3133462282% of 3474200= 497274.27466 m
Following the same steps are before. Using the cylinder volume calculator we get the volumes to be:
505px: 7.0718821e+23
517px: 6.7474035e+23
Same as before, We just mutliply with the pulverisation and vaporisation values.
505px:
7.0718821e+23x214.35= 1.5158579e+26 High 6-A Multi-Continental
7.0718821e+23x25700= 1.8174737e+28 High 6-A Multi-Continental
517px:
6.7474035e+23x214.35= 1.4463059e+26 High 6-A Multi-Continental
6.7474035e+23x25700= 1.7340827e+28 High 6-A Multi-Continental