1)Jilius stops the car[]
In one of the chapters of the manga, we see how Jilius stops a racing car without even budging. At first I thought it was a Class 5 feat or a maximum of Class 10, but I decided to use the braking distance formula to find out the real values of this feat.
Let's start by finding the speed of the car. Bolid accelerates from 0 to 100 km/h in 1,5 econds. I think we can apply this to this car, since the company obviously would not save for this experiment.
100 km/h = 27.7 m/sec;
a = (V1-V0)/t = 27,7/1,5 = 18,46 m/sec^2;
Now we have to find the speed that the car managed to develop, and for this we will find the distance that it drove.
In the first frame, we can calculate the distance between the car and Jilius.
Jilius' height = 2.05 m = 180 pixels;
The average height of the wheel of the car = 0.6 m = 80 pixels;
Panel height = 620 pixels;
We also see that the head of Jilius is 20 pixels, which gives us a value of 0.227 m. This will come in handy later.
Distance to Jilius = 2.05*620/(180*2tan(70/2)) = 7.45 meters;
Wheel distance = 0.6*620/(80*2tan(70/2)) = 4.9 meters;
The distance between the Jilius and the car = 7.45 - 4.9 = 2,55 meters;
The car managed to cover a certain distance before stopping. We'll find him.
Wheel height = 0.6 m = 34 pixels;
Panel height = 1200 pixels;
Distance to the car = 0.6*1200/(34*2tan(70/2)) = 22,34 meters;
Now we can find the path that the car has overcome:
S = 22.34 - 2.55 = 19,79 meters;
S = (at^2)/2 = 19,79 m;
at^2 = 19,79 * 2 = 39,58;
t^2 = 39,58/a = 39,58/18,46 = 2,144
t = √(2,144) = 1,46 seconds;
It took the car so long to cover this distance.
Now, knowing the time and acceleration, we can calculate the speed that the car managed to develop:
V = 18,46*1,46 = 26,95m/sec (slightly more than 97 km/h)
The mass of the car = 746 kg (the maximum allowed by the regulations with a pilot and fuel);
KE = (756*26,95^2)/2 = 274 542 joules;
However, Jilius did not even budge and the car braked as soon as the chain rested on his muscles. Therefore, I will take the depth as far as the links have sunk into the muscles and use them as a braking path.
Jilius head = 0.227 m = 172 pixels;
Link width = 21 pixels = 0,227/172 * 21 = 0.027 m;
F = 274 542/0,027 = 10,168,222 Newtons = 1142 Tons = Class M;
Not bad.
2)Now we will look at the power feat of Wakatsuki, which he performed in the manga Kengan Zero when he was still a child.
Fortunately, it is much easier to calculate than the previous one.
Wakatsuki was placed in a special medical center, where he was monitored and helped to live in comfortable conditions. Here we see that he, unable to control his power, breaks a joystick made especially for him from titanium. It sounds powerful, especially for a child. But for how long?
At the time of the events of the chapter, he was 7 years old.
The average height of a seven-year-old child according to statistics = 1.25 meters;
Average weight = 22 kg;
Wakatsuki has an abnormal muscle density 52 times higher than the muscle density of an ordinary person. However, at that age he did not begin to gain weight, so I will assume that he is 4 times heavier than an ordinary child, as it was when he was born.
Weight = 88 kg;
Body area = 1.60 m^2;
The human hand is approximately 0.83% of the total surface area of the body.
Arm area = 1.60 * 0.083 = 0.01328 m^2;
Since he uses two hands, we will increase the result by 2.
Area = 0.02656 m^2;
Yield strength = 175 MPa;
F = 175*10^6*0,02656 = 4 648 000 Newtons = 473,964 kg = Class K;
I think this gives a strong K+ Class for Kengan and should scale only to the most physically strong characters of the verse, such as Wakatsuki, Jilius, Ryan, Toa Mudo and possibly Lu Tian with Guihun.
3)Well, let's calculate a similar feat from Kanoh in order to scale the rest of the characters of the verse before that. During the cuming out of Nico Tiger, Agito loses his temper and in anger squeezes the handrail with all his strength. Metal handrails are usually made of aluminum, so we can calculate this.
Kanoh height = 2.01 m
Head = 1/8 of height = 2.01/8 = 0.25125 m = 150 pixels;
The length of the deformed part = 160 pixels = 0,25125/150 * 160 = 0.268 m;
Handrail diameter = 15 pixels = 0,25125/150 * 15 = 0.025125 m;
S=πDh
S = 3,14 * 0,025125 * 0,268 = 0.02114319 m^2:
Yield strength of aluminum = 20 MPa
F = 20*10^6*0,02114319 = 422 863 Newtons = 43 120 kg;
Kanoh can use two hands, so multiply the result by 2.
LS = 86 240 kg = Class 100+;
Well, now they are even closer to Baki verse.
4)Jilius crushes the barbell[]
Jilius' height = 2.05 m = 484 pixels;
Neck diameter = 15 pixels = 2,05/484*15 = 0.063 m;
Fingerboard length = 375 pixels = 2,05/484*375 = 1.58 m;
Diameter of the rod disc = 150 pixels = 2,05/484*150 = 0.63 m;
Fingerboard surface area = S=ΠDH = 3,14*0,063*0,63 = 0.1246266 m^2;
Disk surface area = S=πr^2 = 3,14*(0,315^2) = 0,311 m;
Both are made of steel
Yield strength of steel = 350 Mpa
F1 = 350*10^6*0,1246266 = 43619310 Newtons = 4447 Tons of force = Class M;
F2 = 350*10^6*0,311 = 108850000 Newtons = 11099 Tons of force Class M;
5)Ohma drags a boar[]
Well, the LS feat for characters not included in the top in strength.
In the first chapters behind the scenes, Oh ma drags the carcass of a huge boar into the house. Let's find its mass.
Floor height = 4.3 m (average height) = 65 pixels;
Window height = 25 pixels = 4,3/65*25 = 1.65 meters;
Let's move on to the frame with the boar:
Window height = 205 pixels;
The height of the boar = 450 pixels = 1,65/205*450 = 3.62 meters;
For comparison, I will take a large specimen of a wild boar, because our specimen has a massive complexion even for its height.
The average height of a boar at the withers = 1 meter;
Average weight = 275 kg;
We use the law of the square of the cube.
Weight = 275 * 1*3,62^3 = 13045 kg = Class 25
1)Class M - ACCEPTED
2)Class K - REJECTED
3)Class 100 - REJECTED
4)Class M - ACCEPTED
5)Class 25 - ACCEPTED