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VS Battles Wiki
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Hello, everyone! Migue79 here with another calculation blog. And this time, I will be calculating an assortment of Invincible feats as requested here. Whichever ones are possible and worthwhile, at least.

Null lifts an entire town[]

Feat here.

We are thankfully told a town of reference for this calc: Deerfield, Kansas. So, I'll use the total surface area of the place for reference.

Surface area of Deerfield: 1.25 km2 or 1,250,000 m2

Radius: 630.783131 m2

Assuming the depth of this chunk of earth where the town lies on top of is the same as the radius...

Volume: 525,652,609 m3

Mass: 525,652,609 m3 * 1330 kg/m3 = 699,117,969,970 kg (Class G)

This is probably higher due to the chunk of soil appearing to be much greater than I estimated in a few shots.

Mark chucks half of a meteor to the Moon[]

Feat happens here.

This golem formed from a meteor that Mark previously tried to stop, but ended up re-directing. So, I will find the meteor's mass and then find it's KE as Mark chucks it to the Moon.

Now... I WOULD use pixelscaling for the feat, but unfortunately, none of the shots provided to me really work for pixelscaling: from these would give a meteor that wouldn't even be above 10 meters in diameter which doesn't make sense given the context of the scene, and while this does show how large the meteor is within the contect, I cannot really scale it off of anything as it is in a different plane. Therefore, I will assume that the meteor is at least 150 meters given the context of the scene where it is a clear threat that will be hazardous to the Earth and that we at least can see it's larger than that decently big lunar building.

Volume: 471.2 m2

Mass: 471.2 m2 * 3700 kg/m3 (Density of Chrondites, what asteroids are made of) = 1,743,440 kg

And this golem was formed from this meteor. As seen in the first set of scans, the golem was torn in half and chucked to the Moon (so 871,720 kg). Given it takes an entire page for the half of the golem to reach the Moon (which is 384,400 km away from Earth by the way), I will assume 2 ends: a 10 second end, and a 30 second end. For the former end, it will be a speed of 38,440,000 m/s. And for the latter, it will be 12,813,333 m/s.

Applying Relativistic KE...

Low-end: 71658341913324989821 Joules or 17.127 Gigatons of TNT (Island level) (Accepted)

High-end: 652093234192883223450 Joules or 155.854 Gigatons of TNT (Large Island level)

About what I expected.