so gildarts is surrounded by laser beams
we see that some of these beams 's source balls are placed off screen , so as a low ball
i can say that the distance of fartheset laser ball is ATLEAST viewport distance
to find the view port distance we can use angle sizing
the screen height =740 px
gildarts height =84.5 px
angle=2x tan inverse( tan (35)/(screen height/gildarts height) )
=2x tan inverse(tan (35)/(740/84.5))
= 9.14285 degrees
solving for distance in
and assuming gildarts to be 180 cm tall
we get the viewport distance = 11.256 m
gildarts cape width/range =145.75 px =3.105 m
it is also seen that the lasers are ATMOST within the range of gildarts cape
so we can lowball and say gildarts reacts and counters withing the time for lasers to reach his body from cape's outmost boundary
so c*t= 3.105/2 =1.5524 m
so time frame t = 5.17456x10^-9 s
let us say gildarts took half of all his time left to react and other half to counter attack
the range of gildarts attack is supposed to reach all the laser balls .
so range of attack >= viewport distance = 11.256m
therefore speed of attack = range of attack / time taken
= 11.256*2/5.17456x10^-9 =14.5 x C
this is ftl+