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In the Mob Psycho 100: Psychic Battle Official preview, Mob does a huge explosion that can be seen from the sky with his psychic powers.

Mobfeat1232123












The known diameter of the Earth is 12742 km. If 629p = 12742km, then 1p = 20.2575km. 

The explosion seems to have a diameter of 12.5p, or a radius of 6.25p, or 126.60km.

Assuming this, the explosion covered an area of 50352 squared kilometers. 

R = Y^(1/3)*0.28 is the formula for non-nuclear explosions, where R is the radius in km and Y is the energy in kilotons.

Applying it, we get that Y = 92432994.53, so the explosion yields 92432994.53 kilotons or 92.4323 gigatons. 6-C+.


ADDITION

Absaddie gave me the idea to also calc the KE of the stones that are thrown to space. Thanks.

Runningwithbananasaaaaa(2)












12742 km = 525p. So 1p = 24.27km.

To make things easier i'll assume the rocks have spherical shape. I'll be calc'ing the 3 biggest rocks.
The volume of a sphere is 4*Pi*R^3 / 3
Rock 2 has 13.6p of diameter or 165km of radius. The volume, then, is 18816014.25 ck or 18816014250000000 cubic meters.
Rock 1 has 12.17p of diameter or 154km of radius. The volume, then, is 15332716.8 ck, or 15332716800000000 cubic meters.
Rock 3 has 8p of diameter or 97km of radius. The volume, then, is 3822995.72 ck, or 3822995720000000 cubic meters.
Continental crust, stone and earth: 2700 Kg/m^3.
So, for each piece of earth we have:

2 --> 50803238475000000000kg; 1 --> 41398335360000000000kg; 3 --> 10322088444000000000kg.

One of the rocks travelled 54 pixels in half a second. So we have about 2620000m/s. The KE formula is 0.5 x m x v^2. In this case: 2 -- > 174366875093895000000000000000000J 1 --> 142087366622592000000000000000000J 3--> 35427471957496800000000000000000J

For a total of 351881713673983800000000000000000J or 84.1 Zettatons, 5-B.

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