Totally Accurated Battle Simulator Thor Hammer falls on Legacy Map

Feat bellow

Context: T.A.B.S is a sandbox game where You put down troops to fight each other, There is a lot of maps for then to fight in the game, one beingh "Legacy Map" in that Map most troops need to unlooked by finding itens relating to then hidden arounf the map, one beingh Thor hammer sitting in a big Crater inside a Broken Small castle and with a bunch of burned trees around giving heavy implications that the hammer made all of this, This calcs are focused on discovering how much power Thor Hammer has Behind It's atacks

Finding a ruler

First of all we need to find a object with no size variation in the game that can be placed anywhere, so It's good for us that weapons in the game don't change size, i choosed the monk staff since It's a straight stick and can actually be placed vertically, for this I will be using something better then averge human height since wooblers aren't even human nor have gender, Leonardo da Vinci is in the game, so I took a bunch of his dead body to make sure It's not any of the variating sizes and putted It on the simulation map to get the size of the squares in pixels

then I used It to get the staff lenght as can be seen bellow

Cool, now let's keep going, Wikipedia say he had 1,75 meters im height so let's use that

289/68 = 1,75/X > X = 0,411765, let's just turn this into 0,4 meters

Now let's get the staff

43/141 = 0,4/X > X = 1,31 meters, let's do the same here and turn into 1,3 meters

Now that we have our ruler we can start

Hole

I will start with the creater since It seen easier to do, here are the size messurements:

Let's start just getting the values:

163/200 = 1,3/X > X = 1,6

107/525 = 1,3/X > X = 6,38

So now we know that Hole has a Diameter of 6,38 meters (Or a radius of 3,19 meters) and a deepht of 1,6 meters, so let'sget the volume of It as a Ellipsoid and then take half out since I have no idea how to get only Half of a Ellipsoid faster

Volume = (4 × π × a × b × c)/3

V = (4 × π × 3,19 × 3,19 × 1,6)/3

V= 68.2 M^3

V/2 = 34.1 m^3

Okay, the volume of dirty destroyed is 34 M^3

But sinse some of the soil was pushed out in the sides of the creater let's remove 10% of this amount: 30,6 M^3

Soil fragmentation is 0.15 J/cc, It's violent fragmentation is 0.2 J/cc

Fragmentation: 30600000 x 0.15 = 4590000 Joules (Accepted)

Violent Fragmentation: 30600000 x 0.2 = 6120000 Joules

Both are 9-B

Castle

Now we also have a small building(castle) on top of that, so here are the height messurements, for the lenght we will just guess It was a square of the same size as the crater since It possible was a bit larger then the crater considering how far apart the It's debries are from the hole It self. Here are the messurements

We don't need to calc the lenght of the castle since we alread found It when doing the hole, so the Castle block is a square with 6,38 meters on each side. Now for the castle height, we have It's towers height and It's walls height, I will only do the walls since the towers are mostly undamaged and the castle should have a averge height closer to the walls

153/277 = 1,3/X > X = 2.35 meters Now let's get the volume, I know It should be mostly empty but I will take care of this soon 6.38 x 6.38 x 2.35 = 95.65534 m^3 or 95.65 m^3 But now how we get the empty space? well...

Now we have how thick the walls were, let's just use the same value for the cealling and floor too:

300/79 = 1.3/X > X = 0.342333 m or 0.34 m Now, let's just remove that value form each meassurement twice so we know how much empty space there was in volume and subtract with the original volume we got 0.34 x 2 = 0.68 meters 6.38 - 0.68 = 5.7 m 2.35 - 0.68 = 1.67 m 5.7 x 5.7 x 1.67 = 54.2583 m^3 or 54.25 m^3 95.65 m^3 - 54.25 m^3 = 41.4 m^3 Okay, now for the destruction It self, The castle seen to be made of Limestone so Let's use It: Limestone fragmentation is 10 J/cc, It's violent fragmentation is 50-140 J/cc My guess is that this is just normal fragmentation, still will calc both ends of violent fragmentation just to be sure

Fragmentation: 414000000 x 10 = 414000000 J - 9-A

Violent Fragmentation 1: 414000000 x 50 = 20700000000 J - High 8-C

Violent Fragmentation 2: 414000000 x 140 = 57960000000 J - 8-B (Accepted)

As I said earlier, probable the correct one probable is the 9-A one

now we only have one left! the:

Crater + Castle

Well. this is easy. Sinse that the hammer made the Crater and destroyed the castle at the same time let's just add the values together

RA = 4590000 J TER = 6120000 J AS = 414000000 J TL = 20700000000 J E = 57960000000 J

C	AS	TL	E
RA	418590000 J 9-A	20704590000 J high 8-C	57964590000 J 8-B
TER	420120000 J 9-A	20706120000 J high 8-C	57966120000 J 8-B

We have then 6 possible ends and the RA + E end was Accepted

HEAT WAVE (Not Accepted)

As You can see bellow the crash burned a bunch of trees, this should apply to normal AP of the hammer sinse every hit of It makes eletric effect, bellow is the messurements, I will use the creater diameter to calculate this one:

As You probable can see, the circle isn't centered, I decided would be better to just make a circle around the trees instead of making sure It's in the middle sinse otherwise not burned trees would be inside It

Now for the calc It self

145/580 = 6.38/X > X = 25.52 m of diameter or a radius of 12.76 m

from here I don't really know how to calc so must of It will be based of a calc made for another wiki so there is a good chance of something beingh wrong:

Trees flash burn at around 800'C

But let's see a detailed way to see It too

Volume of Flash Heated Air = 8702.43188 m³

Density of Air at 15'C (average outside temperature) = 1.225kg/m³

Mass = 8702.43188 * 1.225 = 10660.479053 kg

Change in Temperature = 800 - 15 = 785'C

Specific Heat Calculator:

Joules for room condition air = 8091303601 Joules

Joules dor sea level/dry air = 8023343047 Joules

So... Top of 8-C

Burned trees (Not Accepted)

Now, with the help of BreezeHM who explained to me another way to make this calc

first of all We determining the Area

using the radius of 1276 Meters to determine the area

Using the Area of a circle we get, 51151 m^2

Determine the amount of trees.

There is 12 trees

Mass of Each Log

Mass of Oak Wood is 26582 kg per tree.

Moisture Content

Moisture Content of Oak wood is 75%

Removing Moisture from Wood

For this, we'll use the latent heat of vaporization for water (2257 J/g)

First we'll convert the moisture content to grams by multiplying it by the mass.

75% x 26582000 grams (26582 kg) = 19936500 grams

Now the Energy Required to remove the moisture from the wood

Joules = Moisture Content * Latent Heat Vaporization

Joules = 19936500 grams * (2257 J/g) = 44996680500 joules

Carbonization

Oak wood has a heat capacity of 2380 j/kg°C

Oak Tree has a temperature of 55°F thats 1278°C

Tree logs go black at around 600 degrees Celsius

(ΔT) = T1 - T2

(ΔT) = 600 - 1278 = 58722°C

Energy = Mass (kg) × Specific heat capacity (J/kg°C) × ΔT (°C) × 1000 (to convert grams to kilograms)

Energy = 26582 kg x 2380 j/kg°C x 587.22°C = 37 279 570 184

Pre Final Tally

44996680500 + 37279570184 = 82276250684

So It takes 82276250684 Joules to turn one tree black.

Since there is 12 trees we multiply by 12

82276250684 x 12 = 987315008208 joules

987315008208 Joules is 235 Tons

8-A, Multi-City Block level

Finally all the ends

1. 418590000 J 9-A (Crater + Castle 1)
2. 420120000 J 9-A (Crater + Castle 2)
3. 8023343047 J 8-C (Heat wave)
4. 20704590000 J high 8-C (Crater + Castle 3)
5. 20706120000 J high 8-C (Crater + Castle 4)
6. 57964590000 J 8-B (Crater + Castle 5) (Accepted)
7. 57966120000 J 8-B (Crater + Castle 6)
8. 987315008208 J 8-A (Burned trees)