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Calculation done by retired Calculation Group member over discord and first time I'm making a blog.

Feat in question

Version 1: Average Height[]

According to these sources provided to me by Bambu the average height for an 18 year old Japanese male is 171 cm and given how this is a Japanese made game it would be be fair to use this.

Okie Dokie - Image 1 (There's 3 of these):

Character = 87px Average Height = 171cm

1px = 1.71 / 87 = 0.0196551724m

Rock = 378px 0.0196551724 * 378 = 7.42965517m

Moving on to the next image...

XB3 size calc








Next 2 Images: Rock Base = 173px

1px = 7.42965517 / 173 = 0.0429459836m

Rock Length = 970.71px 0.0429459836 * 970.71 = 41.6880957m

Rock Width = 528.5px 0.0429459836 * 528.5 = 22.6969523326m

Rock Height = 262px 0.0429459836 * 262 = 11.2518477032

Xb3CalcSize
Xb3CalcSize2

















Now that we have our dimensions, we can find volume (Assuming it's a Semi-Ellipsoid): https://rechneronline.de/pi/semi-ellipsoid.php

(Note that width and height are halved for the values used in this calculator to find the radius) Volume of the rock = 5574.451m3 Onto the final part, the feat itself... We'll do this 2 ways for now (since I cant find a reliable way to get this as a cracking calculation...)

Fragmentation: Simple enough, we already have our volume, Fragmentation of Stone is 8 J/cc Rock Volume = 5574.451m3 = 5574451000cc

Energy = 5574451000 * 8 = 44595608000 Joules = 10.658606118547 Tons of TNT Large Building Level (High 8-C)

Next up, our second, likely more reasonable method imo. I'm gonna do a GPE calculation for this, my reasoning for this is that the rock was being held up by the pillar, and wasn't falling due to this, meaning that pillar was sustaining the Gravitational Potential Energy of the huge cliff. The character damaged this pillar enough to break apart the rock on top, causing it to fall, so we should be able to use this.

Also simple enough: GPE = Mass * Centre of Height * Gravity

We just need to find the Centre of Height...

With our new Lime Line (232.84px), we can find how high the rock is held up: Using our pixel scale from our 2nd & 3rd images...

232.84 * 0.0429459836 = 9.99954282142m Ez

Assuming this rock is Granite (This seems like a mountainous area and mountains are generally made of this, plus its a general very common rock) Density = 2700kg/m3

Meaning our Mass = 2700 * 5574.451 = 15051017.7kg

Plugging this into our GPE formula: 15051017.7 * 9.99954282142 * 9.81 = 1476437333.73 Joules - 1.47643733373 Gigajoules - 0.3528769918092735 Tons of TNT Building Level (8-C)

Xb3CalcSize3












Version 2: Estimated Height[]

This version of the calc instead uses an calculated estimation of the character Noah's height based on this bio which tells us that the height of the transformed version of the Consul is 5 meters. HeightXb3

Using this image we get a new value of 199 cm instead of 171 cm.

Fragmentation goes as follows: Pixel Scale Difference = 1.99 / 1.71 = 1.16374269x

Volume Difference 1.16374269^3 = 1.57605329x

Old Fragmentation = 44595608000 Joules New Fragmentation = 44595608000 * 1.57605329 = 7.02850547e+10 Joules - 16.79853123805 Tons of TNT


Next, new GPE: First off we're changing the Centre of Mass Height: Old Height = 9.99954282142m New Height = 9.99954282142 * 1.16374269 = 11.6368948618m

Now we need the new mass, which scales to the Cube value of the difference: Old Mass = 15051017.7kg New Mass = 15051017.7 * 1.57605329 = 23721205.9639kg

New GPE = 23721205.9639 * 11.6368948618 * 9.81 = 2707963973.81 Joules = 0.6472189229947418 Tons of TNT

Tally:[]

Fragmentation with Average Height: 10.658606118547 Tons of TNT High 8-C+

GPE with Average Height: 0.3528769918092735 Tons of TNT 8-C

Fragmentation with Estimated Height: 16.79853123805 Tons of TNT 8-B (ACCEPTED)

GPE with Estimated Height: 0.6472189229947418 Tons of TNT 8-C

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