Executive Summary[]
Assorted Godzilla feats
Remake - Godzilla vs Mothra 2[]
Lucifer Queen of the Underworld suggested to:
Remake of the following feat calcs taking into account the suggestions of the calc group members?
User blog:TheJ-ManRequiem/Godzilla Vs. Mothra 1992 2 - Credits to TheJ-ManRequiem unless I specifically make changes that I deem essential. I will make such changes (if any) clear.
Godzilla vs Mothra 2 - Mothra diverts a meteor[]
At the end of the film, almost as a poetic encircling of the plot, the Cosmos twins (seemingly the last surviving pair of a prehistoric fairy humanoid race) relay to the humans of a unfathomable threat to their existence: a massive asteroid is directly en route to a collision with Earth sometime in the late 1990s, with very ominous consequences for those 'in the way'.
But never fear! The Cosmos reassure the farewell party that Imago Mothra is capable of physically diverting the meteor from its path and redirect it out of harm's way.
But how much energy would it require to accomplish such a task?
The precise size of the incoming asteroid is not specified, with the most information we have to go on still being somewhat vague in nature: that it is (presumably) large enough to trigger a sufficiently great cataclysm for humans to recognise its impact as "destroying Earth".
Now, this could very well mean that the bolide is capable of generating a great enough energy output upon impact to overcome Earth's GBE (2.24e+32 joules or ~53 zettatons of TNT equivalent) and irrepairably destroy the entire planet as its fragments disperse infinitely. The dialogue certainly does not exclude such rationale as a possible conclusion.
However, it's a sufficiently wishy-washy phrasing of the question (at least IMHO) that the Cosmos affirmation could just as easily qualify for the asteroid being big enough to cause sufficiently major damage to the Earth's biosphere and trigger a mass-extinction event that would wipe out humanity (the main species concerned with the incident). Which would still be tremendously powerful, but orders of magnitude weaker than total planetary destruction.
So let's approach the asteroid size with two avenues: (1) minimum bolide size capable of triggering a mass-extinction event and (2) minimum bolide size capable of overcoming Earth's GBE.
(1) Mass-Extinction
This should be a simple demonstration, given the extensive amount of research having been dedicated to a universally verified meteor impact in our prehistory, currently cited as the most probable cause for a mass-extinction which wiped out approx. 75% of contemporary species on the planet: the K-Pg/K-T extinction event, and more precisely, the Chicxulub impactor/crater.
Studies indicate that the impactor responsible for the Chicxulub crater would have to be a minimum size of 10 km in diameter. The only other two impact zones known to science that are 100% verifiable asteroid impacts and larger than Chicxulub, Vredefort in South Africa and Sudbury Basin in Ontario, Canada, are also believed to have been caused by impactors measuring in the 10 - 15 km diameter range, thus demonstrating a fair consistency in qualifying a "mass extinction" asteroid at the 10 km mark.
Assuming a decently symmetrical/ovular ellipsoid shape for the Chicxulub impactor (axis A = radius; axis B = 1/2 of axis A length; axis C = axis B):
Volume of an ellipsoid =
= 1.31e+11 m^31.309E+11 m^3
As for the density: the Chicxulub impactor is currently believed to have originated as a member of the [http://en.wikipedia.org/wiki/Flora family Flora family of S-type asteroids within the Asteroid Belt; Florian asteroids are highly plausible candidates to being the 'parent' family to L chrondite meteorites, which in turn have an average density of 3.35 g/cm^3.
3.35 g/cm^3 = 3350 kg/m^3
Mass = 1.31e+11*3350 = 4.389e+14 kg4.38514E+14 m^3
Average orbital velocity of an asteroid around our Sun is 25 km/s, which will probably best match up to our giant rock buddy here, particularly given that there's no figures for deep space-traversing asteroids.
= (0.5)*4.38514e+14*25,000*25,000 = 1.37140625e+231.37036E+23 joules or 32.7832.75 teratons of TNT equivalent.
But the "mass-extinction" avenue is, ultimately, the lower rung of the cosmic wazoo ladder.
How big would the impactor need to be in order to overcome Earth's GBE?
In short: a rogue celestial body approximately [http://www.madsci.org/posts/archives/1999-07/931435915.As.r.html 3/5 (or 60%) the mass of Earth itself.
Earth's mass is 5.96e+24 kg5.97237E+24 kg
Earth celestial body mass = 5.96e+24/5 = 1.192e+24 kg; 1.192e+24*3 = 3.576e+24 kg 3.58342E+24 kg
Assuming the same cosmic velocity...
KE = (0.5)*3.576e+24*25,000*25,000 = 1.1175e+33 1.11982E+33 joules or 267.09 267.643 zettatons of TNT equivalent.
Fucking. Yikes.
Jasonsith comments: Figure correction aside, I wonder why the velocity is needed from the Earth. Or has momentum theory been explained though? Like, should we simply add the GBE of the Earth plus the fragmentation energy of the meteorite and get the yield?
---
An important note: the Cosmos twins state that prior to Battra's premature awakening and subsequent death at the hands of Godzilla, it was to emerge and transform into its Imago state around the deadlineof the meteor's appearance, then outrightdestroy the bolide prior to its impact when "in range" (presumably, "in range" = far enough that Battra doesn't risk collateral damage to Earth via asteroid fragmentation, but near enough so that Imago Battra can fly back to the planet in a relatively short span of time).
Much earlier in the film, when describing the artifical birth of Battra by the Cosmos civilisation 12,000 years prior to the modern day, Battra is explicitly stated to have equivalent energy output to Mothra.
So powerscaling either the low-end or high-end (lololol) result to Imago Battra and Second Mutation Heisei Godzilla is pretty much a dead cert.
Godzilla vs Mothra 2 - Mothra diverts a meteor - Spino Method[]
Assume the meteor correspond ti a similar Chicxulub Impact Event...
AP = 1.3E+24 J / 310 teratons TNT (Large Country ) to 5.8E+25 J / 13.8 petatons TNT (Multi-Continent)
Mass = 1E+15 kg (Class P) to 4.6E+17 kg (Class P)
Godzilla vs Mothra 2 - Mothra flaps its wings[]
9# - Flight Speed (Imago Mothra)
It is nearly over, I swear - J-man's words, not mine.
Mothra in Imago state departs the Earth, along with the Cosmos twins, to traverse into deep space and re-direct the giant asteroid. It manages to fly past the planet's atmosphere in a remarkably short timeframe as the film concludes.
Spoiler: http://i.imgur.com/W8Cb6Cb.png (Warning: image may appear huge as shit. If so, apologies~)
Angsize formula:
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70 deg/2)))
PoV-Mothra Angsize: 49.214099009724 degrees
PoV-Earth Angsize: 89.615848642702 degrees
Inputting those values into the angsize calculator:
PoV-Mothra Distance: 191.05 metres PoV-Earth Distance: 3,558,700 metres
3,558,700 - 191.05 = 3,558,508.95 metres is the 'true' distance.
3,558,508.95/1000 = 3558.51 km
For the timeframe:
1:38:14 - Mothra last seen in atmosphere.
1:39:01 - First view of Mothra with Earth in background.
Thus, the sequence duration is 47 seconds.
3558.51/47 = 75.71 km/s or Mach 222.49
Correlates quite well with the previously calculated speed of Imago Battra, though obviously quite a bit higher at the same time. Again, outside of Imago Battra, no beneficial powerscaling to other daikaiju, IMO.
Godzilla vs Mothra (1992) - Part 3 Energy Output (Huge Asteroid, Kinetic)* = 32.78 teratons [low-end] - 267.09 zettatons [high-end] of TNT equivalent. Speed (Imago Mothra, Flight)** = Mach 222.49
- = My immediate and overwhelming rationale for this would be to stick to the low-end unless one can irrefutably prove to the contrary; implication otherwise is that even Burning/Meltdown Godzilla is practically a flea in energy to the casual performance of Mothra and/or Battra.
- = Should also apply to Imago Battra's flight/combat speed.
Remake - Godzilla Final Wars[]
Remakes of feat calcs from Godzilla Final Wars - Credits to TheJ-ManRequiem unless I specifically make changes that I deem essential. I will make such changes (if any) clear.
Flight Speed (Rodan)[]
Quite a few feats to cover in this section, as Rodan is one of the few showcased daikaiju to really get to strut its stuff.
Feat #1
In its debut appearance, Rodan roars pasta UN charter plane carrying the newly elected Secretary-General, Japanese national Naotaro Daigo, its sonicboom 'wake' destroying the plane in the process.
I'll be presenting two different methods on calculating the velocity of Rodan in this sequence.
Method #1
Spoiler:
Method #1, focus only on the lilac and grey font; meant to read 11 frames in lilac writing)
The film is in [http://i.imgur.com/ICbfRGi.png 24 FPS.
11/24 = 0.46 seconds
244.24244.4454054/0.46 = 530.96533.3354 m/s (Mach 1.55)
Like I said, straightforward and direct.
Method #2
The second approach is a little more elaborate; instead of using frame-by-frame analysis of Rodan itself, I propose scaling the distance traveled by the charter plane (with a RL velocity) between the start and finish of the sequence, to determine a 'new' timespan by which to extrapolate Rodan's aerial speed.
This is where the dark green font in the spoilered image above becomes relevant.
Picture comparison of cloud position between sequence start and end.
I'm no expert on airplanes, but the UN doesn't get provided custom models for charter flights, and it appears to mostly resemble a 747-400, so that's the type I'll go with. The 747-400 has a cruising velocity of Mach 0.85 (289.24 m/s)
59.1559.20162162/289.24 = 0.20450145208131660.204679925
seconds is the new timespan.
Now, Rodan travels 244.24 metres in the exact same sequence that the 747-400 crosses 59.15, so therefore I'll apply the new timeframe to Rodan's distance.
244.24244.4454/0.20450145208131660.204679925
seconds =1194.321194.281 m/s (Mach3.513.48187 )
A much more suspectible calc with plenty more potential for patchwork assumptions in play.
Feat #2
Squaring off against the EDF's aerial battleship Rumbling in the ruined New York City, Rodan demonstrates another burst of speed as it flies from over the Rumbling in the span of a couple frames.
Spoiler: for FW Rodan [http://www.tohokingdom.com/kaiju/rodan mill.htm wingspan and Rumbling height)
Angsize to be deployed en masse~!
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2))) Image #1 Angsize calculator
Angsize: 115.020927962452 degrees PoV Distance: 63.68 metres*
Image #2
Ang: 26.787902952798 degrees PoV Distance: 62.99 metres*
Image #3
Ang: 48.503240721718 degrees PoV Distance: 33.30 metres*
Image #4
Ang: 28.872326038864 degrees PoV Distance: 38.21 metres*
- = Yes, somehow the smaller-sized object in the background manages to be closer to the PoV than the expansive mass in the immediate foreground. Don't ask me how the hell I accomplished that; I'll be focusing on the Rumbling-derived distances due to it being the object traversed.
62.99 + 33.30 = 96.29 metres is traveled by Rodan, roughly.
Timespan is 5 frames.
5/24 = 0.21 seconds
96.29/0.21 = 458.52 m/s (Mach 1.35)
Not really all that impressive, plus the angsize snarl might not make my methodology even all that accurate in regards to this feat.
All speed displays by FW Rodan can probably be scaled to FW Kamacuras, Mothra in Imago stage and Gigan in flight, as well as the physical reflexes of FW Godzilla (capable of casually intercepting both Kamacuras and Rodan in mid-air) and Monster X/Keizer Ghidorah (the only daikaiju in the entire film to actually trouble Godzilla in combat).
Jasonsith comment: I am not commenting on this. I cannot replicate the above finding.
Flight Speed (Kamacuras)[]
3# - Flight Speed (Kamacuras)
Since I never bothered to cover Son of Godzilla due to lack of relatively quantifiable feats, this is actually the compendium debut of Kamacuras!
Simple enough premise here.
Spoiler:
Link (Source for FW Kamacuras' body length)
18/24 = 0.75 seconds
523.64523.6363636/0.75 = 698.19698.18 m/s (Mach 2.05Mach 2.035516)
As mentioned above; this can probably be scalable to FW Rodan in flight.
Gotengo[]
Gotengo - Feat #1[]
Spoiler:
(Picture) 2f/24fps = 0.08 0.083333333 seconds
Gotengo is 150 m long = 578.4981 px here
Gotengo projectile 1 length = 280 px = 72.60179981 m
Projectile speed = 74.5972.60179981 m / 0.08 0.083333333 s = 932.375 m/s (Mach 2.74)871.2215977 m/s (Mach 2.540004658)
Gotengo - Feats #2 & #3[]
Spoiler: (Picture) Blue Line
Referring to the lenght of Gotengo to the projectile #2, projectile #2 trajectory length = 390 px = 101.1239354 m
Speed = 103.90101.1239354 m / 0.08 0.083333333 s = 1298.75 871.2215977 m/s (Mach 3.82 2.540004658)
Orange Line
Referring to the lenght of Gotengo to the projectile #3, projectile #3 trajectory length = 615 px = 159.4646674 m
4f/24fps = 0.17 0.166666667 seconds
Projectile speed for #3 = 163.84 159.4646674 m / 0.17 0.166666667 seconds = 963.76 956.7880046 m/s (Mach 2.83 2.789469401)
The same deal applies as the X-ian beam weapons in terms of extremely conservative velocity figures, given that the Gotengo's weapons propagated exactly the same as their enemies'.
Gotengo - 8# - Beam Speed (Atomic Breath)[]
Now, we're hitting the water spring of the well of feats obtainable from this film.
Both low-end and high-end assumptions will be supplied for this calc.
Gotengo - 8# - Beam Speed (Atomic Breath) - Low End[]
The LE of the feat actually relies on certain distance markers from the calculation immediately following this one, namely that the meteor begins its calculable descent sequence at a measured altitude of 1864.70 km.
What makes this figure crucial, is that the AB directly connects with the Monster X meteor several seconds prior to reaching the start of the calculated descent, meaning that at bare minimum, the meteor's altitude at the moment the AB strucck was at least 1864+ kilometres above sea level.
1:28:48 - Godzilla initially fires the AB at ground level. 1:28:50 - The AB has passed Earth's outer atmosphere (and the 1864+ km marking point).
Therefore, the feat duration was 2 seconds.
1864.70/2 = 932.55 932.35 km/s (Mach 2740.56 2718.221574)
Gotengo - 8# - Beam Speed (Atomic Breath) - High End[]
The ceiling for the beam speed is a little less simplistic, and draws upon directly scaling from the visual given at 1:28:50 filmtime.
Spoiler: (picture) This interpretation relies heavily on the notion that the PoV section of Earth is not noticeably distorted and/or skewed so that the given layout remains uniformly within the 'circle' indicated by the visible curvature, and more importantly, that Japan's geographical position is on the very opposite 'curve' within this hypothetical 2-D shape to the visible slice, along with the AB originating from that particular angle and precise location.
Quite a few assumptions, all in all.
Anyway, feat time span remains the same as the low-end.
14,519.50/2 = 7259.75 km/s (Mach 21,334.78 | 0.0242 c | 2.42% the speed of light)
I'd recommend mostly to stick with the LE value, at least until I can potentially justify usage of the HE more favourably.
Naturally scales with the beam speeds of both Monster X (who largely equalled 'base' FW Godzilla in combat) and Keizer Ghidorah (who casually overwhelmed 'base' FW Godzilla with practically zero difficulty).
Gotengo - 9# - Projectile Stats (Monster X Meteor)[]
Velocity
Spoiler: (Pic 1) (Pic 2) (Source for Hokkaido vertical length is a previous Pokemon-related calc of my own)
Angsize is necessary for determining the travel distance.
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))Angsize calculator
Image #1
Ang: 13.942911505704 degrees PoV Distance: 1864.70 kilometres
However, one also has to factor in that more than half of the meteor's own length is itself ahead of the PoV: while it wouldn't ultimately distort the final result remotely dramatically, it would not be particularly dignified of me to simply ignore the fact, so I'll be generous and assume that:
1) The meteor's diameter is = in size to the total height of Monster X, which is 120 metres.
2) That the total diameter is actually ahead of the PoV rather than just a majority of the length; this is more out of convenience for myself.
1864.70 - 0.120 = 1864.58 km
Image #2
Ang: 21.143673198324 degrees PoV Distance: 1221.70 kilometres
1221.70 - 0.120 = 1221.58 km.
1864.58 - 1221.58 = 643 kilometres is the travel distance of the meteor between Images #1 and #2.
Feat timespan is 17 frames. 17/24 = 0.71 seconds.
643/0.71 = 905.63 km/s (Mach 2661.44)
Really doesn't need to scale to anything other than the meteor itself, given that there's nothing to validate assigning such speeds to Monster X or Keizer Ghidorah themselves once in-atmosphere, and the fact that beam speeds themselves derive from an even faster calculation.
Kinetic Energy
With the projectile velocity provided, we can now discern the KE output of this meteor with full momentum.
For mass, I'll once again substitute the given value of daikaiju Monster X (60,000 metric tons) for the unknown weight of its meteorite form.
60,000 metric tons = 60,000,000 kg 905.63 km/s = 905,630 m/s (0.5)*60,000,000*905,630*905,630 = 2.460497091e+19 joules or 5.88 gigatons of TNT equivalent.
It appears that I was correct < This is a comment made by b
Remake - Manda[]
Remakes of feat calcs from [https://vsbattles.fandom.com/wiki/User blog:Gallavant/Manda (Godzilla) survives the mantle reactor%27s explosion (Calc) Manda Durability - Credits to Gallavant unless I specifically make changes that I deem essential. I will make such changes (if any) clear.
First I will start off with some relevant information:
- Manda is a giant sea dragon monster from the Godzilla universe.
- The Mu civilization worships it as a diety
- The Mu civilization can collapse parts of cities (such as downtown Tokyo) through unknown, likely magnetic means
- Mu used to be a fictional continent in the Pacific Ocean
- The remaining civilization after their continent sank created a geothermal reactor right above (perhaps in?) the mantle for power
"206
00:18:49,500 --> 00:18:53,401
The Mu people far surpass
the people who live on earth.
207
00:18:53,470 --> 00:18:55,215
With terrestrial heat we made a sun.
208
00:18:56,000 --> 00:18:59,000
We live at the bottom of the sea
by using buried resources."
- Their reactor was stated to be located six miles, or 9.65 kilometers beneath the ocean floor.
"
☀704
01:23:54,796 --> 01:23:57,697
We will rule the world.
705
01:23:58,800 --> 01:24:02,998
Killing me cannot kill our Empire’s
heart!
706
01:24:03,138 --> 01:24:04,901
Empire’s heart?
707
01:24:05,206 --> 01:24:09,666
It’s the power room using
terrestrial heat for Mu energy.
708
01:24:10,111 --> 01:24:11,476
Where is it?
709
01:24:12,781 --> 01:24:15,648
It’s located at six miles below the
Palace."
- Gotengo froze Mandausing its Zero cannon at a temperature of Absolute Zero to the undersea cliffs above the Mu city
- Gotengo drilled 9.65 kilometers through oceanic crust and destroyed the reactor.
-Manda survived and re-appeared in Destroy All Monsters, the last movie in the Showa continuity.
Part 1:
Shortly after the explosion starts, Mu submarines appear in front of the explosion, trying to escape.
These submarines are 130 meters long according to Tohokingdom: first its just one: [ (Please disregard the green line, it is irrelevant) another appears, behind the first one, yet still in front of the massive explosion, in the foreground
Since the submarines may be facing different angles, I will scale off the apparent size of the top part of the submarines [ So the second submarine is 2 and a half times farther away. That should mean if the first submarine in the Part 1 were 2.5x as far away, or appearing 2.5x smaller, it would still be in front of the explosion! Meaning 135 / 2.5 = 54 pixels in front of the explosion actually equals at least, likely more than, 130 meters. And since the explosion is over 858 pixels wide.. 3:
It provides a minimum diameter for the explosion, and 1032.78 meter radius! [ explosion volume.png/revision/latest?cb=20150803234336 Volume: 32,300,000,000 cubic meters or 32300000000000000 cubic centimeters, or 32.3 cubic kilometers of rock!
Applying violent fragmentation value (120 j/cc)
Results in 3.876e+18 Joules, 926 Megatons, or Mountain level+, just under the Small Island level minimum of 4.184e+18 Joules
Conclusion:
This likely justifies Mountain level or similar durability to quite a few other Showa era kaiju, Manda is just an unimportant side monster in the Godzilla series (appearing only in one of his movies as actual footage rather than stock footage) and one of the strongest monsters can clear planetary surfaces such as Venus's on its own as well as survive its own attacks.