Feats from Vietnamese movie, Superman X (Siêu nhân X).
Call an Ambulance![]
Superman X stopped an ambulance with one hand.
Type 2 Ambulance weight = 4173.5 kg
The average speed of ambulance is 15 mph or 6.7 m/s.
Super X took roughly a second to stop the ambulance.
Deceleration = 6.7 / 1 = 6.7 s/m^2
Force = Mass x Acceleration = 27962 Newtons
27962 / 9.81 = 2850 Kg (Class 5)
I could also calculate KE from the feat as well.
KE = 1/2 * 4173.50 * 6.7^2 = 93674 Joules (Wall level)
Thugs Jump Very High[]
In this scene, the thugs was able to jump up to a building so I will calc the force they need to exert to do it.
The building is 8 stories so its height is 35 m based on this calculator.
Average weight/height for Vietnamese man is:
Weight = 61.2 kg
Height = 164.44 cm
Potential Energy = 206067 J (Wall level)
I will use 1/3 body height for the jump
206067 / (1.6444 / 3) = 375943 Newtons
375943 / 9.81 = 38322 kg (Class 50)
On the other hand, I could calc how fast they need to jump to reach that height.
Displacement = (initial velocity * time) + 1/2 * acceleration * time^2
35 = (0 m/s * t) + 1/2 * 9.81 * t^2
35 = 0 + 4.905 * t^2
35 / 4.905 = t^2
sqrt(7.13) = t
t = 2.670 seconds
2.670 * 9.81 = 26.19 m/s (Superhuman)
Results[]
- Stopped an ambulance with one hand = 2850 Kg (Class 5) / 93674 Joules (Wall level)
- Jumped on top of a building = 206067 J (Wall level) / 38322 kg (Class 50) / 26.19 m/s (Superhuman)