Assumptions/Data[]
So after browsing a few websites, I found two that gave me the info needed.
I will calculate only two different table types (the two that are usually the most common) which is the dinning room table and the coffee table. Dimensions of both can be found here
According to this website, the common thickness of a wooden table goes from from 1" to 1 ¾" So this can effectively be our low and high balls.
Now, I was trying to find a good source for what wood is most common for tables, and the only one was this. It says Oak is the most common so I will assume that kind of wood for the tables.
The tensile strength of white oak is 5.3 MPa
and the modification factor is 0.8
We will use the formula for force of shearing, where shear force = area sheared x shear stress, shear stress being the tensile strength of the material x 0.8 (the modification factor for wood)
The Calculation[]
Dinning Room Table[]
The table has the width of 40 inches, the length of 64 inches, and the thickness of 1 - 1.75 inches.
40 inches = 1.016 meters (width)
64 inches = 1.6256 meters (length)
1 inch = 0.0254 meters (height)
1.75 inches = 0.04445 meters (height)
Now to find the area of the table. We will use the area formula for a rectangular prism which is A = 2 (wl+hl+hw)
Low-ball
A = 2 ((1.016 x 1.6256) + (0.0254 x 1.6256) + (0.02540 x 1.016)) Total area is 3.43741248 m^2
(0.8)(5.3x10^6 N/m^2)(3.43741248 m^2) >Simplify> (0.8) x (5300000) x (3.43741248) = 14574628.9152 newtons
Work = (14574628.9152 N)(0.0254 m) = 370,195.574446 joules
High-ball
A = 2 ((1.016 x 1.6256) + (0.04445 x 1.6256) + (0.04445 x 1.016)) Total area is 3.53805744 m^2
(0.8)(5.3x10^6 N/m^2)(3.53805744 m^2) >Simplify> (0.8) x (5300000) x (3.53805744) = 15001363.5 newtons
Work = (15001363.5 N)(0.04445 m) = 666,810.608 joules
Coffee Table[]
The table has the width of 18 inches, the length of 36-48 inches, and the thickness of 1-1.75 inches.
18 inches = 0.4572 meters (width)
36 inches = 0.9144 meters (length)
42 inches = 1.0668 meters (length)
48 inches = 1.2192 meters (length)
1 inch = 0.0254 meters (height)
1.75 inches = 0.04445 meters (height)
Now to find the area of the table. We will use the area formula for a rectangular prism which is A = 2 (wl+hl+hw)
Low-Ball (Using Lowest length and lowest height)
A = 2 ((0.4572 x 0.9144) + (0.0254 x 0.9144) + (0.0254 x 0.4572)) Total area is 0.90580464 m^2
(0.8)(5.3x10^6 N/m^2)(0.90580464 m^2) >Simplify> (0.8) x (5300000) x (0.90580464) = 3840611.67 newtons
Work = (3840611.67 N)(0.0254 m) = 97,551.5364 joules
Mid-Ball (Using the Average Length and lowest height)
A = 2 ((0.4572 x 1.0668) + (0.0254 x 1.0668) + (0.0254 x 0.4572)) Total area is 1.05290112 m^2
(0.8)(5.3x10^6 N/m^2)(1.05290112 m^2) >Simplify> (0.8) x (5300000) x (1.05290112) = 4464300.75 newtons
Work = (4464300.75 N)(0.0254 m) = 113,393.239 joules
High-Ball (Using the highest length and highest height)
A = 2 ((0.4572 x 1.2192) + (0.04445 x 1.2192) + (0.04445 x 0.4572)) Total area is 1.26386844 m^2
(0.8)(5.3x10^6 N/m^2)(1.26386844 m^2) >Simplify> (0.8) x (5300000) x (1.26386844) = 5358802.19 newtons
Work = (5358802.19 N)(0.04445 m) = 238,198.757 joules
Conclusion[]
Dinning Room Tables[]
Low-Ball = 370,195.574446 joules or 88.4788658 grams of tnt - Wall Level
High-Ball = 666,810.608 joules or 159.371560229 grams of tnt - Wall Level
Coffee Table[]
Low-Ball = 97,551.5364 joules or 23.3153767686 grams of tnt - Wall Level
Mid-Ball = 113,393.239 joules or 27.1016345602 grams of tnt - Wall Level
High-Ball = 238,198.757 joules or 56.9308692639 grams of tnt - Wall Level