Flamethrower Ultra-Robot Melts and Blows Away Multiple Buildings
Takes place after Jack Training to Jump Good Samurai Jack Episode 18
The Flamethrower Ultra-Robot easily destroys three buildings in a row before unleashing an attack that destroys multiple buildings at once.
The Ultra-Robot isn't to scale with the destruction in the after photo. The position of structures in the before picture do not match the position of the remains in the after picture.
If we based buildings size from only the second picture's 16px, they would be 3-5 m wide.
|Ultrabot Head Width||0.66394||17|
|Base Building Width||20.58214||527|
|Base Building Width||20.58214||99||20.58214||120.375||20.58214||158|
|Hemisphere Volume (m^3)||13651452.37||5533008.913||1717272.653|
|Air Density (kg/m^3)||1.225||1.225||1.225|
|Air Mass (kg)||16723029.15||6777935.919||2103659|
|Average temperature (Kelvin)||293.15||293.15||293.15|
|Steel Melting Point (Kelvin)||1643.15||1643.15||1643.15|
|Temperature increase (Kelvin)||1350||1350||1350|
|Specific Heat Capacity (J/kg*K)||717.8||717.8||717.8|
|Energy (J)||1.62E+13||Low 7-C||6.57E+12||Low 7-C||2.04E+12||8-A|
At least 8-A Multi-City Block Level
Likely Low 7-C Small Town
If we take into account that the attack also blew everything away, the result would again increase.
Samurai Jack's Speed and Moving a Gauntlet
Samurai Jack: Season 3, Episode 8
Jack and Glass Dome of Death. Jack casually reacts and dodges sunlight.
I made GIF where I highlighted feat specially for You :
Ok, let's extract 2 following frames.
Looks like Jack traveled roughly the same distance as light. Let's find out the exact ratio between Jack's and sunlight's speeds. A little bit of Paint will help us with the ratio.
So, when I connect these 2 pictures, I get this one.
Let's get our ratio.
Multiplier = 398 / 508 = 0.7834645669291339 ~ 0.8Jack's combat speed and reactions
Jack's speed = 80% of lightspeed = Relativistic+
Samurai Jack dodges multiple light beams from the Sun.
The calc itself has been done with a result of 80% the speed of light and accepted. This is kinda calc scaling, but there's another aspect of this that we can add; relativistic kinetic energy. The average weight of a Japanese man is 67.6kg.
T = 299792458 X 80/100 = 239833966m/s
Putting that through the RKE calculator and we get 4.044E+18 joules or 966.539196941 megatons. Seeing as though he's wielding a giant golden gauntlet bigger than himself, this would certainly be higher.
I did a calc of this feat involving the Gauntlet awhile back to celebrate Season 5. Here's a do-over.
Assuming Jack is 1.7 Meters, that would give the gauntlet a diameter of about 1.08 Meters and a length of 0.9 Meters.
pi × r2 × h
pi × 0.54^2 × 0.9 = 0.824 m^3
Using Density of Iron (I forgot if it was said to be a certain material)
7,874 * 0.824 = 6488.176 kg
It's not completely solid, so I'll use 80% hollowness.
6555.176 - 80% = 1311 kg
1311 + 67 = 1378 kg (I think Jack has an official weight that's over 100 kg, but I forgot the source).
Samurai Jacks Relativistic Kinetic Energy = 8.243E+19 Joules. 19.7 Gigatons = 6-C Island level