Superman Escapes a Black Hole[]
Superman scapes the pull of a miniature black hole. This is from Action Comics Annual Vol 1 #7 (November 1995, I know this was published after the Byrne era but it is supposed to be Byrne Era Superman)
Low End[]
Frankly, this makes more sense, but a black hole has an escape velocity of light speed, so the energy to escape its pull is going to be e = mc^2
Superman weighs 225 lb according to secret files
225 lb * c^2 = 2.19228993 gigatons of tnt (High 7-A)
High End[]
Superman is 190.5 centimeters in height
Superman = 38x517 pixels = 518.39463731794139770287907861472 pixels = 190.5 cm
Black Hole = 303x104 pixels = 320.3513695928269322435082654614 pixels = 117.72293 cm
https://www.omnicalculator.com/physics/schwarzschild-radius
Gravity = 76,344,954,949,457,819 m/s^2
Assuming Superman took about 6 meters from the scan, that is 76,344,954,949,457,819 m/s^2 * 6 meters * 225 lb = 11.1734728 gigatons of tnt (6-C)
Mon-El Pushes a White Dwarf[]
This comes from Legion of Super-Heroes Vol 3 (July 1988). For the feat in question, I don't think we can just assume it's 4-C. It's not that large
Here is the White Dwarf:
Mon El is 6'2", here he is 219 pixels which = 187.96 cm
White Dwarf = 517 pixels = 443.723 cm
I cannot calculate kinetic energy here because he crossed interstellar distances, but I can calculate lifting strength.
Low End[]
https://www.omnicalculator.com/math/volume
With a diameter of 443.723 centimeters, it has a volume of 45.7 cubic meters
White Dwarfs have a density of 1e+9 kilograms per cubic meter, which gives it a mass of 45,700,000,000 kilograms (Class G)
High End[]
http://farside.ph.utexas.edu/teaching/sm1/lectures/node87.html
A RL White Dwarf has a surface area of 615,752,160 square kilometers and the white dwarf here, 61.8548 square meters.
(615,752,160 square kilometers)/(61.8548 square meters) = 9.95479995e+12
The mass of a RL White Dwarf under these scenarios is 2e+30 kilograms
= 2.00908106e+17 kilograms (Class P)
Superman tanks a Suneater Implosion[]
The feat is from Adventures of Superman #477 (April 1991) and the original calculation comes from here:
https://www.narutoforums.org/xfa-blog-entry/calc-requests-part-21.33441/
However the original calculation uses two different Suneaters from two different issues. ThThe "50x the Kepler Supernova" one is referring to Action Comics Vol 1 #847 (April 2007) and the situation is different. The Sun-Eater doesn't have one consistent yield when it explodes; it runs off the energy it absorbed from a Star and uses that to propel itself. In the case for the 2007 feat, it very well could be that the Star the Suneater absorbed was just much bigger and the ensuing explosion from the entropy bomb was 50x Kepler's supernova. However, here, we aren't entertained such notion and are told constantly this is just "A Sun," so I will use that information to calculate the energy theoretically held by the Suneater and use that as the implosion value.
Low End[]
The Sun has a Luminosity of 3.846(10)^26 watts and has a maximum lifespan of 10,000,000,000 years
3.846(10)^26 watts * 10,000,000,000 years = 1.21367937 foe (High 4-C)
Wildfire was at the core of the explosion.
I could only find one source for his height, which applies to the Pre-Crisis version, but I figure there's no reason to assume it would have changed so it's usable.
Wildfire height: 6' (1.8288 m)
Panel width: 586 px Panel height: 441 px
Angsizing:
2*atan(tan(70/2)*(586/441) = 85.87234358795
2*atan(84.97531622/(586/tan(85.87234358795/2))) = 15.368054760248 degrees
Angsize calculator gives a distance of 6.7773 m from the PoV.
Post-Crisis Superman official height: 6' 3" (1.905 m)
Angsizing:
2*atan(346.5207883/(586/tan(85.87234358795/2))) = 57.63883618461 degrees
Angsize calculator gives a distance of 1.7312 m. Since they're roughly on the same line, we can subtract to get the distance between them as 5.0461 m.
Superman being at 100 kg in weight, has a surface area of 2.29 m^2, divided by two we get 1.145 m^2
Surface area of a sphere with radius 5.0461 m = 319.9790684 m^2. Dividing, we get 279.457702, so Superman tanked 0.00434298057 foe or 103,799,727 yottatons of tnt (Low 4-C)
High End[]
Fusion requires tritium with an atomic mass of 3.0160492 u and deuterium with an atomic mass of 2.01410177811 u.
http://www.mccc.edu/~dornemam/Planet_Walk/Sun/the_sun.htm
Going by this, 2 deuterium and 2 tritium atoms would fuse
6.0320984 atomic mass units + 4.02820356 atomic mass units = 10.060302 atomic mass units
The article uses 600 million tons of hydrogen as a theoretical
600 million tons of tnt/10.060302 atomic mass units = 3.25826856(10)^37
And the remaining 4,000,000 tons comes off as energy, or the luminosity of the sun which is more accurately 3.846(10)^26 joules
3.846(10)^26 joules/3.25826856(10)^37 = 73.6736204 megaelectron volts
The Sun is 1.98847(10)^30 kilograms and hydrogen makes up 73% of it's mass. That is 1.4515831(10)^30 kilograms.
1.4515831(10)^30 kilograms/10.060302 atomic mass units = 8.68924004(10)^55
8.68924004(10)^55 * 73.6736204 megaelectron volts = 10.2566184 foe (High 4-C)
Using the ratio from earlier, we get 0.0367018634 foe or 877,195,588 yottatons of tnt (High 4-C)
However, I actually do not believe Superman took much of the explosion's energy, if any.
For context, Superman had some form of chronon matter on him which made high bursts of energy transport him across time. Superman being hurt and disoriented is a result of going through time, worse than even what is emphasized as his most impressive feat (at the time) of surviving a 40 megaton nuclear bomb.
However, every time these explosions happen, he seems to be more afflicted and emphasizing of the time travel resulting from the explosion. In fact, this can be seen by how he doesn't remember the actual nuclear explosion which sent him back in time, again implying he isn't actually taking the full brunt of these explosions and is simply being dumped in time the instant the energy touches him, regardless of amount.
Lastly, we have this statement from an editor. Going by this, people will be able to survive these explosions too but die from the actual time travel, which is consistent with Superman being more affected by the time travel than the actual explosion. Given a regular person will survive an explosion under these conditions, that means they obviously don't take much energy of the explosion, which transitively implies Superman likely did not actually take the force of the suneater explosion. As such, while the feat may be high 4-C for the explosion itself, it very likely does not apply to Superman's durability as he was under special conditions where the actual energy from the explosion instantly dumps him in time rather than out and out harms him.
Eradicator creates a Sunspot[]
Superman: Man of Steel Vol. 1 #1 (July 1991)
Eradicator creates a sunspot, I will use an oval to find the rough (high-balled) size of the Sunspot
- 758 pixels = 1391400 km
- 64x49 pixels = 80.60397012554654556244602404408 pixels = 147958.26389536340830552427157643 km
- 49x158 pixels = 165.42369842317031209436173698027 pixels = 303655.05802902265468086401165481 km
https://keisan.casio.com/exec/system/1223289167
141,146,339,421.45 square km
The pixel area is 10,472.347407755 square pixels
Here is the sunspot:
Using a histogram on gimp, I get the sunspot to be 4043 square pixels
141,146,339,421.45 square km * (4043/10,472.347407755) = 54,491,569,851.69726376725 square kilometers
http://articles.adsabs.harvard.edu//full/1990IAUS..138..273H/0000273.000.html
The magnetic flux of a sunspot is 0.15 teslas
54,491,569,851.69726376725 square km * 0.15 teslas = 8.17373548 petawebers
The current of a sunspot is 1e12 amperes
8.17373548 petawebers * 1e12 amperes = 1.95356967 exatons of tnt (High 6-A)
Superman Hit with the Force of a Nova[]
In Justice League America Vol. 1 #64 (July 1992) Superman is hit by Starbreaker "With the force of a Nova," which according to this site:
http://astronomy.swin.edu.au/cosmos/C/Classical+Novae
Is equal to 1(10)^37 joules, or 2390.05736 yottatons of tnt, or in the 5-A range