Jungle Juice: The Dean Cuts Clouds

In Chapter 68, the Dean misses the Leader's neck, and the attack ends up parting the clouds behind him, so I'mma calc that.

Note:

I'm measuring the clouds by using the angular diameter of the moon, which is on average about half a degree. I am also using this calculator, set on Size.
Judging by their dark and fuzzy look, as how it's raining the next day, and how the rainfall was specifically referenced in a later chapter (see these Images), I'm assuming these are nimbostratus clouds, which are 2000 - 4000 meters thick, so I'll use 3,000 meters.
The Nimbostratus Cloud Base itself is pretty low hanging, being from 0 to 2 km- "often very close or even touching the ground", and between low levels to 3000 meters, with an altitude as low as 500m. It does look fairly low hanging (see images), so using the cloud base being 500 meters above ground, and the cloud itself is 3000 meters thick, that means the top of the cloud will be 3.5 kilometers above the ground. Since the cut goes through the entire cloud, that means the apparent diameter of the cut's lengths will be from 3.5 km away. Using 609.6 meters as the cloud base height in light of the Cloud Calculations CRT. So now the other height will be 3609.6 meters-

ATTACK POTENCY: Calc images (here)

The Moon: 186 pixels
Space Parted: 90.02 pixels
Cut Length: 641 pixels
Cloud Width 421.9 pixels
~~Angular size of Parted Space: 0.5 / 186 * 90.02 = 0.2419892473 degrees~~
~~The width of something 3500 meters away and 0.2419892473 degrees in size is: 14.782 meters~~
~~Angular size of Cut Length: 0.5 / 186 * 641 = 1.72311828 degrees~~
~~The width of something 3500 meters away and 1.72311828 degrees in size is: 105.27 meters~~
~~Angular size of Cloud Width: 0.5 / 186 * 421.9 = 1.134139785 degrees~~
~~The width of something 3500 meters away and 1.134139785 degrees in size is: 69.283 meters~~

Alright, doing it manually using this formula- Object size = 2*tan(70deg/2) * distance from point of view to object * object height in pixels / panel height in pixels, but with 0.5 degrees instead of 70 degrees as the angular size of the Moon, and the Moon's height in pixels instead of panel height.

Space Parted Size: 2*tan(0.5/2) * 3609.6 * 90.02 / 186 = 15.24527527 meters
Cut Length Size: 2*tan(0.5/2) * 3609.6 * 641 / 186 = 108.5561147 meters
Cloud Width: 2*tan(0.5/2) * 3609.6 * 421.9 / 186 = 71.45058472 meters

Now then, dividing the Parted Space width by two gets the distance traveled by the cloud on each side of the cut, so-

15.24527527/2 = 7.622637635 meters

Assuming a 1 second quick action timeframe means the parted clouds had to move 7.62 m/s.

~~Meanwhile getting mass- multiplying the length and width by the thickness of a nimbostratus cloud gets-~~

~~105.2599738 * 69.28109666 * 3000 = 21,877,579.26 m3~~

~~Multiplying by cloud density gets mass so-~~

~~21877579.26 * 1.003 kg/m3 = 21,943,212 kg~~

[11/6/22 EDIT: Cloud Calc revision stuff] Multiplying length and width to get m2-

108.5561147 * 71.45058472 = 7756.39787 m2

And then plugging that, plus the elevation (609.6m) and cloud thickness (3000m) into this calculator to get mass yields- 23,230,862.2098 kg

Multiplying by 2 because that's only the cloud on one side of the cut means-

23,230,862.2098 * 2 = 46,461,724.42 kg

And finally putting the mass and speed in the KE equation gets-

46461724.42 * 0.5 * 7.622637635^2 = 1,349,820,060 joules

About 1,349.8 megajoules, or Building level. (I think this might just be the weakest cloud moving calc on the wiki.)

SPEED:

Alright so, the Dean does that thing where the person makes a cut, but the objects cut have a delayed reaction and don't split until right as they sheath their sword. In other words I have no idea what timeframe to use. I was gonna use them talking before the cut happened as a low ball, but because "talking is a free action" is taken into account here, words are not allowed to be used for timeframes.

~~I guess just read this scene (here) and choose whichever one fits the best.~~

High End: 1 second (Reason: The Leader's wing and the cloud were both cut, with the sliced off bit of the wing still in the air when the cloud was also parted, although it was a delayed split so it's unclear if the cut traveled from the wing to the cloud in a short time, or if the cut took longer, and both just parted at the same time when the Dean sheathed his sword thanks to delayed reaction Rule of Cool)- 3500/1 = 3500 m/s, or Hypersonic+
Mid End: 5 seconds (Reason: Standard 1 Panel Timeframe like in all of these calcs)- 3500/5 = 700 m/s, or Supersonic
Low End: 10 seconds (Reason: They exchanged bits of dialogue, which should've taken this long, assuming that talking speed is valid in this case)- 3500/10 = 350 m/s, or Transonic

Alright, I'll use another way recommended to me by KLOL- instead of how fast the cut-arc traveled to the clouds, we can get the speed of the actual cut itself by dividing the length of the cut with the draw speed of a pro-swordsman. Original Video from (here)- slowed down footage from (here).

The video has been slowed down by 10 times, turning a 4.55 second long video into a 45.50 second long video- the action is so quick that the blade itself literally doesn't render briefly after the dude draws it due to the rolling shutter not being fast enough, so I'll have to go by the dude's hands. Individual Frames (here)

The man starts to unsheathe between 15.75 and 16.11- I'll use starting time at (15.75+16.11)/2= 15.93 as an average
The handle rotates out from 16.39 to 17.45
The handle is motionless as the shutter catches up to the blade from 17.82 to 19.09
The actual draw was from 15.93 to 17.45, or 1.52 seconds in 10x slow-mo, meaning an IRL time of 0.152 seconds

The cut length was 108.5561147 meters- so 108.5561147/0.152 = 714.1849651 m/s, or Supersonic