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We're calculating the energy necessary to destroy a standard pool (billiard) table.

The Slates[]

We're starting with the stone slabs that make up the table's playing field.

https://en.wikipedia.org/wiki/Billiard_table

According to wikipedia we have two standard sizes for the playing field.

One is 254 cm x 127 cm (9ft table) and the other is 234 cm x 117 cm (8ft table). Or in area: 32258 cm^2 and 27378 cm^2.

The slates must be at least 2.54 cm. That gives us the volumes: 2.54 cm * 32258 cm^2 = 81935.32 cm^3 and 2.54 cm * 27378 cm^2 = 69540.12 cm^3

Now, taking the destruction values for slate from our destruction value table:

Low End:

  • Fragmentation: 69540.12 cm^3 * 15 J/cc = 1.0431018e6 J
  • Violent Fragmentation: 69540.12 cm^3 * 103.42 J/cc = 7.1918392104e6 J
  • Pulverization: 69540.12 cm^3 * 172.5 J/cc = 1.19956707e7 J

High End:

  • Fragmentation: 81935.32 cm^3 * 15 J/cc = 1.2290298e6 J
  • Violent Fragmentation: 81935.32 cm^3 * 103.42 J/cc = 8.4737507944e6 J
  • Pulverization: 81935.32 cm^3 * 172.5 J/cc = 1.41338427e7 J

For the next part I also want to figure out the weight of the slate. Density is 2600 kg/m^3.

Our high-end volume (9ft) was 81935.32 cm^3 = 0.08193532 m^3 and the low-end volume (8ft) was 69540.12 cm^3 = 0.06954012 m^3.

Multiplying with density:

  • High end (9ft): 0.08193532 m^3 * 2600 = 213.031832 kg
  • Low end (8ft): 0.06954012 m^3 * 2600 = 180.804312 kg

Wood[]

That leaves the wood to destroy. Now those tables have a lot of parts, so measuring the volume of the wood is bothersome. So instead, I will go by weight.

According to this an 8ft pool table with slate weights 1000 Pounds = 453.592 kg and a 9ft pool table weights 1,300 Pounds = 589.6701kg.

We have calculated the weight of the slates above, so we can substract those.

453.592 kg - 180.804312 kg = 272.787688 kg of wood

589.6701 kg - 213.031832 kg = 376.638268 kg of wood

Now I will need to make a guess at the type of wood. This producers lists several options. I will simply use the thing on the top of the list: Oak. I will use white oak specifically, as the calculation page suggests that as standard assumption.

According to this that type of wood has a density of 0.77*10^3 kg/m^3.

That gives us a volume of:

  • Low end: 272.787688 / (0.77*10^3) = 0.3542697246753247 m^3 = 354269.7246753247 cm^3
  • High end: 376.638268 / (0.77*10^3) = 0.4891406077922078 m^3 = 489140.6077922078 cm^3

Now applying the destruction values for that wood from our calculations page:

Low End:

  • Fragmentation: 354269.7246753247 * 7.3774 = 2613589.46681974044178 J
  • Violent Fragmentation: 354269.7246753247 * 13.7895 = 4885202.36841038995065 J
  • Pulverization: 354269.7246753247 * 51.297 = 18172974.0666701311359 J

High End:

  • Fragmentation: 489140.6077922078 * 7.3774 = 3608585.91992623382372 J
  • Violent Fragmentation: 489140.6077922078 * 13.7895 = 6745004.4111506494581 J
  • Pulverization: 489140.6077922078 * 51.297 = 25091445.7579168835166 J

Summing Up[]

Now to sum up slate and wood for the final result Low End:

  • Fragmentation: 2613589.46681974044178 J + 1.0431018e6 J = 3.65669126681974044e6 J Wall level
  • Violent Fragmentation: 4885202.36841038995065 J + 7.1918392104e6 J = 1.207704157881039e7 J Wall level+
  • Pulverization: 18172974.0666701311359 J + 1.19956707e7 J = 3.0168644766670131e7 Small Building level

High End:

  • Fragmentation: 3608585.91992623382372 J + 1.2290298e6 J = 4.83761571992623382e6 J Wall level
  • Violent Fragmentation: 6745004.4111506494581 J + 8.4737507944e6 J = 1.5218755205550649e7 J Wall level+
  • Pulverization: 25091445.7579168835166 J + 1.41338427e7 J = 3.9225288457916884e7 J Small Building level