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So this is the feat I was given for this calc.

So how much energy would it need to burn humans to ashes?

Data[]

Assumptions[]

Should thousands be taken literally here? Well, I will leave that for discussion, for now I will take to values:

  • I count at least 17 of them in the picture, so that is one value.
  • Thousands would be at least 2000, so that is the second value.

Calculation[]

760 °C - 37 °C = 723 °C = Tempertaure they have to be heated upon.

3470 J/(kg * °C) * 88.3 kg * 723 °C = 221527923 Joules = Energy to burn one human.

221527923 Joules per human * 17 humans = 3.765974691*10^9 Joules = Value 1 = Building Level

221527923 Joules per human * 2000 humans = 4.43055846*10^11Joules = Value 2 = Multi-City Block level


He can probably also take that much, given that he can fly with that much friction.

Uncertain Calculation part 2[]

Now that much is the energy made through friction. Now technically in order to produce that much energy through friction one requires a lot mroe energy as kinetic energy when flying. Now in order to calculate that I will first have to figure out a speed from the friction, but there are two problems with that:

  1. There is no data for friction at that high speed, so I will approximate using data for lower speeds
  2. Much more important: The speed can not be used as speed feat, since in general speed derived from energy calculation isn´t accepted. That much is clear. This is furthermore problematic, since I am very sceptikal about the kinetic energy being used, if the speed shouldn´t be used in the first place. I will still calculate it, mostly because I never used friction calculation for something before, but I don´t expect that to be accepted. (actually it should certainly not be accepted, looking at the end result)

Data[]

Calculating speed[]

For simplicity, and since I don´t have anything else to go by, I will say the generation of teh energy was done in 1 second.

Then we can set in:

Value 1[]

3.765974691*10^9 Joules = 0.5 * 1.2041 kg/m^3 * 0.68 m^2 * 0.6 * v^3

Solving to v gives us: 2484.2476694874680577 m/s. Mach 7 lower then expected.

Value 2[]

4.43055846*10^11Joules = 0.5 * 1.2041 kg/m^3 * 0.68 m^2 * 0.6 * v^3

Solving to v gives us: 12172.746 m/s. Mach 41. Not bad.


Kinetic Energy calc[]

Assumin 88.3 kg for Stardust (its a american alien it seems, so why not?).

Value 1:[]

88.3 kg * (2484.2476694874680577 m/s)^2  * 0.5 = 2.7247112824007540611714*10^8 Joules. That is lower than the result in friction... whut?!?

Value 2:[]

88.3 kg * (12172.746 m/s)^2  * 0.5 = 6.5419591497197814* 10^9 Joules. Also lower than the original result.


Soooo... somethings wrong there, but I do quite frankly not know what. Lesson from that: I should not use friction calcs like that...