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In Chapter 162 of Kimetsu no Yaiba, Doma creates a giant Ice Sculpture, so I’m gonna calc it

Photo 1:

Kanao’s Height = 1.56 Meters = 278.84 px

1.56 Meters/278.84 px = 0.0056 Meters per px

Ice Sculpture Head = 444 px = 2.5 Meters

Photo 2:

Ice Sculpture Head = 2.5 Meters = 250 px

2.5 Meters/250 px = 0.01 Meters per px

Ice Sculpture Height = 1681.66 px = 16.82 Meters

Ice Sculpture Width = 936.35 px = 9.36 Meters

Photo 3:

Ice Sculpture Head = 2.5 Meters = 100 px

2.7 Meters/100 px = 0.027 Meters per px

Ice Sculpture Length = 175 px = 4.73 Meters

Volume = (16.82)*(9.36)*(4.73)

Volume = 744.67 Meters^3

E=M*C*ΔT

Density of ice is 920 kg/m^3.

Ice mass = 744.67 m^3*920 kg/m^3 = 685096.4 Kg

Specific heat capacity of water is 4181 J/Kg

We're going to assume -5°C for the ice temperature, and 20°C for the air temperature.

First we need the energy to bring the temperature down from 20°C to 0°C

Energy = (685096.4 Kg*4181 J/Kg*20°C) = 57287760968 Joules

Second we need the energy to bring the temperature down from 0°C to -5°C

Energy = (685096.4 Kg*2108 J/Kg*5°C) = 7220916056 Joules

Now we need the Fusion of Freezing Water

Freezing Water Fusion = 334000 J/Kg

Energy = (685096.4 Kg*334000 J/Kg) = 228822197600 Joules

Yield = 57287760968+7220916056+228822197600 = 293330874624 Joules

Yield = 293330874624 Joules = 70.1 Tons = 8-B (City Block level+)

This should probably scale to the Top 3 Upper Moons and everyone above them

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