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I want to do it first. First, I want to find the size of one explosion across the width of the cracks in the ground. Yes, I know that each crack is different in size. So, I will use more medium-sized cracks. Moreover, the scans through which I will look for the dimensions of one crack show the dimensions of an ordinary crack, which does not stand out from other cracks in size.

Tomorrow I can try to find the diameter of the explosions through the height at which the heroes are. I will search for the height through the angle at which Psykos shoots to get to the top of the tower.

Let's go.

Crack width[]

АС2

The average width of buildings is 15 meters. The line I used to mark the width of the crack was drawn at the same angle as the buildings. So, the line got out a little behind the screen and is not visible. But the dimensions are exactly the same as I indicated on the scan.


15 / 22.4 × 328.3 = 219.84375 meters crack width.











Explosions[]

АС1

I took a slightly large crack, so I definitely won't overestimate the power of the explosion.


219.84375 / 5.8 × 65.1 = 2467.55657328 meters explosion diameter.


W = 1233.77828664^3*((27136*1.37 + 8649)^(1/2)/13568 - 93/13568)^2 = 149534.697599 tons of TNT, or 149.534697599 kilotons.










RESULT[]

10 лучей

As we know, there were several rays. To be precise, 10.

149.534697599 × 10 = 1495.34697599 kilotons, or 1.49534697599 megatons.














New method[]

The method was suggested by Ourosboros and discussed here.

Instead of the detonation formula, we take the deflagration formula. Because, as shown earlier, Orochi's beams in the previous chapters set objects on fire and melted them so that we can use them for clues about the type of explosion.


The explosion height is 95 pixels. Let's say the explosion is half an ellipsoid.

219.84375 / 5.8 × 95 = 3600.88900862 meters height.

Through this site, the volume of the ellipsoid is 22960037342.299 cubic meters. We need half an ellipsoid. As a result, the volume of the explosion is 11480018671.1 cubic meters.

11480018671.1 × 1.3311 × 13062500 × 10 (number of rays) = 1.9960875 × 10^18 joules, or 477.076362333 megatons (Mountain Level, 7-A).



FINAL RESULT[]

  • Low-End = 1.49 megatons (Small City Level, Low 7-B)
  • High-End = 477.07 megatons (Mountain Level, 7-A).

This probably will not affect the power levels of the OPM, but for the first time the Samurai showed a direct achievement for physical strength, without scaling through the characters.

I think that here someone can try to find here the speed of the cuts, because the Samurai cut one beam at once into many other beams. The speed of the beams is sufficient to instantly cross many kilometers and create explosions.

But let someone else do it, not me.

Update[]

A deflagration method has been added. Now, this will affect a lot of dragon-level characters.

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