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Feat[]

Aokiji frozse a large portion of the ocean so that an old man and his horse could cross the distance between four of the islands (essentially walking on the ice three times).

I'll try to calculate from scratch how large the area was that Aokiji froze, and how much energy is took him to do this in order to calculate his AP.

There are two main horizon shots we can use to determine how far Aokiji froze, so I'll be calcing both of these.

Horizon Shot 1[]

Distance between islands[]

This shot of the horizon from the perspective of the characters on the shore if the first one I'll calc.

0319-010 Shore Height

Aokiji's Height = 40 px = 2.98 m

Shore Height = 40 px = 2.98 m

So if we combine the height of the shore above sea level with Luffy's height:

Luffy's Height = 1.72 m

Total Height = 4.7 m

Horizon Distance = 3.57 * √(4.7) = 7740 metres

Full length of the ice[]

Kuzan froze over three islands to get the old man to his destination, so multiple the distance by three:

Length = 7740 * 3 = 23220 m

That gets us the length of ice frozen by Aokiji but we don't know exactly how wide the amount of ice is.

Width of the ice[]

Since the ice appears to extend into the distance in each direction we can assume that it extends as far as the horizon for the characters viewing it.

Width = 4682 * 2 = 9364 m

Area of the ice[]

Area = 23220 * 9364 = 217,432,080 m^2

Low End - Melting Rate[]

For the low end, we'll use the depth previously calculated here.

Depth = 1.06 m

Volume of ice = 217,432,080 * 1.06 = 230478004.8 m^3

Mass of ice = 230,478,004.8 * 1025 kg/m^3 = 236,239,954,920 kg

Maximum Mean Monthly Temperature = 30 degrees

Energy to lower the water's temp = (30,000 calories/kg)(236,239,954,920 kg) = 7,087,198,600,000,000 calories

7,087,198,600,000,000 calories = 29,652,838,942,400,000 joules

Energy to convert to ice = (334,000 J/kg)(236,239,954,920 kg) = 78,904,144,900,000,000 joules

29,652,838,942,400,000 joules + 78,904,144,900,000,000 joules = 108,556,984,000,000,000 joules

108,556,984,000,000,000 joules = 25.95 Megatons

Mid End - Average Tidal Range[]

Tidal depth can vary up to 12 m on average, so I'll use that as a mid end depth.

Depth = 12 m

Volume of ice = 217,432,080 * 12 = 2,609,184,960 m^3

Mass of ice = 2,609,184,960 * 1025 kg/m^3 = 2,674,414,600,000 kg

Maximum Mean Monthly Temperature = 30 degrees

Energy to lower the water's temp = (30,000 calories/kg)(2,674,414,600,000 kg) = 80,232,438,000,000,000 calories

80,232,438,000,000,000 calories = 335,692,520,000,000,000 joules

Energy to convert to ice = (334,000 J/kg)(2,674,414,600,000 kg) = 893,254,480,000,000,000 joules

335,692,520,000,000,000 joules + 893,254,480,000,000,000 joules = 1,228,947,000,000,000,000 joules

1,228,947,000,000,000,000 joules = 293.73 Megatons

High End - Extreme Tidal Range[]

The deepest known tidal range is 16.3 m so I'll use that as a high end depth.

Depth = 16.3 m

Volume of ice = 217,432,080 * 16.3 = 3,544,142,904 m^3

Mass of ice = 3,544,142,904 * 1025 kg/m^3 = 3,632,746,500,000 kg

Energy to lower the water's temp = (30,000 calories/kg)(3,632,746,500,000 kg) = 108,982,400,000,000,000 calories

108,982,400,000,000,000 calories = 455,982,341,000,000,000 joules

Energy to convert to ice = (334,000 J/kg)(3,632,746,500,000 kg) = 1,213,337,330,000,000,000 joules

455,982,341,000,000,000 joules + 1,213,337,330,000,000,000 joules = 1,669,319,700,000,000,000 joules

1,669,319,700,000,000,000 joules = 398.98 Megatons


Horizon Shot 2[]

Distance between islands[]

The perspective of the camera is above one of the trees on the Long Ring Long Land island, so I'll calc a tree in relation to one of the flags on the coast to get a rough estimate for how high the camera is up.

0319-010 Flag Height

Aokiji's Height = 40 px = 2.98 m

Flag Height = 170 px = 12.665 m

0320-004

Flag's Height = 83 px = 12.665 m

Tree Height = 134 px = 20.45 m

Horizon Distance = 3.57 * √(20.45) = 16144 metres

Full length of the ice[]

Kuzan froze over three islands to get the old man to his destination, so multiple the distance by three:

Length = 16144 * 3 = 48432 m

That gets us the length of ice frozen by Aokiji but we don't know exactly how wide the amount of ice is.

Width of the ice[]

Since the ice appears to extend into the distance in each direction we can assume that it extends as far as the horizon for the characters viewing it.

Width = 4682 * 2 = 9364 m

Area of the ice[]

Area = 48432 * 9364 = 453,517,248 m^2

There is no canon value for the depth to which the ice is frozen, so I'll use

Low End - Melting Rate[]

For the low end, we'll use the depth previously calculated here.

Depth = 1.06 m

Volume of ice = 453,517,248 * 1.06 = 480,728,282.88 m^3

Mass of ice = 480,728,282.88 * 1025 kg/m^3 = 492,746,489,952 kg

Energy to lower the water's temp = (30,000 calories/kg)(492,746,489,952 kg) = 14,782,395,000,000,000 calories

14,782,395,000,000,000 calories = 61,849,540,680,000,000 joules

Energy to convert to ice = (334,000 J/kg)(492,746,489,952 kg) = 164,577,330,000,000,000 joules

61,849,540,680,000,000 joules + 164,577,330,000,000,000 joules = 226,426,871,000,000,000 joules

226,426,871,000,000,000 joules = 54.12 Megatons

Mid End - Average Tidal Range[]

Tidal depth can vary up to 12 m on average, so I'll use that as a mid end depth.

Depth = 12 m

Volume of ice = 453,517,248 * 12 = 5,442,206,976 m^3

Mass of ice = 5,442,206,976 * 1025 kg/m^3 = 5,578,262,200,000 kg

Energy to lower the water's temp = (30,000 calories/kg)(5,578,262,200,000 kg) = 167,347,870,000,000,000 calories

167,347,870,000,000,000 calories = 700,183,471,000,000,000 joules

Energy to convert to ice = (334,000 J/kg)(5,578,262,200,000 kg) = 1,863,139,570,000,000,000 joules

700,183,471,000,000,000 joules + 1,863,139,570,000,000,000 joules = 2,563,323,040,000,000,000 joules

2,563,323,040,000,000,000 joules = 612.65 Megatons

High End - Extreme Tidal Range[]

The deepest known tidal range is 16.3 m so I'll use that as a high end depth.

Depth = 16.3 m

Volume of ice = 453,517,248 * 16.3 = 7,392,331,142.4 m^3

Mass of ice = 7,392,331,142.4 * 1025 kg/m^3 = 7,577,139,400,000 kg

Energy to lower the water's temp = (30,000 calories/kg)(7,577,139,400,000 kg) = 227,314,180,000,000,000 calories

227,314,180,000,000,000 calories = 951,082,537,000,000,000 joules

Energy to convert to ice = (334,000 J/kg)(7,577,139,400,000 kg) = 2,530,764,560,000,000,000 joules

951,082,537,000,000,000 joules + 2,530,764,560,000,000,000 joules = 3,481,847,100,000,000,000 joules

3,481,847,100,000,000,000 joules = 832.18 Megatons


Results[]

Horizon 1

  • Low End = 25.95 Megatons (City level)
  • Mid End = 293.73 Megatons (Mountain level)
  • High End = 398.98 Megatons (Mountain level)

Horizon 2

  • Low End = 54.12 Megatons (City level)
  • Mid End = 612.65 Megatons (Mountain level+)
  • High End = 832.18 Megatons (Mountain level+)

So, all that's left is determining which horizon shot we use - I have reasons for preferring the former - and which end for the depth we use.

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