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## Batman catches a baseball

Despite having his back broken, he is fast enough to catch practically without looking a ball hit by a baseball bat when it's inches away from his face (Batman is disguised as Sir Hemingford Gray) (Shadow of the Bat #22)

Bruce Wayne is 188 cm: http://scifi.stackexchange.com/questions/38552/what-is-batmans-height-and-supermans

Human proportions calculator yields 82.1 cm for his arm: http://www.anatomynext.com/hpc.php

90 degrees give or take, so we get 1.57079633 radians

s = 0.821 * 1.57079633

0.821 * 1.57079633 = 1.28962379 meters

Now for the time frame. The baseball should be about 80 mph or 36 m/s, give or take: http://www.efastball.com/baseball/pitching/grips/average-pitching-speed-by-age-group/ Ball was practically frozen between the time it nearly hit Batman and the time he caught it, so using 1 cm

0.01 / 36 = 0.000277777778 seconds

1.28962379 / 0.000277777778 = 4642.64564 m/s or Mach 13.6432033 for catching a baseball

## Method 2 (FanofRPGs)

Bruce Wayne is 188 cm: http://scifi.stackexchange.com/questions/38552/what-is-batmans-height-and-supermans

176 pixels = 28.923 centimeters

2*atan(176/(257/tan(70/2)))

= 35.9544324 degrees

= 44.568 centimeters

panel = 257 pixels

Ball = 79 pixels = 7.468 centimeters

2*atan(79/(257/tan(70/2)))

= 16.5734184 degrees

= 25.637 centimeters

44.568 centimeters - 25.637 centimeters = 18.931 centimeters

Batman Head = 190 pixels = 28.923 centimeters

2*atan(190/(256/tan(70/2)))

38.7494025 degrees

= 41.124 centimeters

Ball = 92 pixels = 7.468 centimeters

2*atan(92/(256/tan(70/2)))

19.3269579 degrees

= 21.929 centimeters

41.124 centimeters - 21.929 centimeters = 19.195 centimeters

Now to find the distance the ball went

19.195 centimeters - 18.931 centimeters = 0.264 centimeters

The average pitch is about 80 mph, or 35.7632 meters per second

(0.264 centimeters)/(35.7632 meters per second) = 73.8188976 microseconds

As said in the calc, his arm moved 1.28962379 meters

1.28962379 meters/73.8188976 microseconds = 17,470.1036 m/s or Mach 51.3389

## Katana reacts to bullets

2*atan(tan(70/2)*(panel_width/panel_height) = FOV

2*atan(tan(70/2)*(859/161) = 150.02944137048 degrees

2*atan(object_size/(panel_height/tan(FOV/2))) = degrees

2*atan(114/(161/tan(150.02944137048/2))) = 138.583747694258 degrees http://en.wikipedia.org/wiki/Katana Katanas are generally around 0.665 meters long and 1.2 kg in mass

Angsize Calculator time and it yields....

Katana/Tatsu is 0.1257 meters away from the camera

AK-47 bullets are generally 715 m/s

0.1257 / 715 = 0.000175804196 seconds

The AK-47's barrel is about 0.0202915452 meters, and 12 pixels or so in that shot. Therefore, I get 31.11987380278 degrees or 0.036436 meters away from the camera.

Tatsu is 1.5748 meters tall according to DC

Arm is 45% of body length

1.5748 * 0.45 = 0.70866 meters

0.70866 + 0.665 = 1.37366 meters moved 90 degrees

1.37366 * 1.57079633 = 2.15774009 meters moved overall

0.1257 - 0.036436 = 0.089264 meters traveled overall for the bullet

0.089264 / 715 = 0.000124844755 seconds

2.15774009 / 0.000124844755 = 17283.386 m/s or mach 50.7901672

0.5 * 1.2 * 17283.386^2 = 179229259 joules or 0.042836821 tons of TNT equivalent which is small building level

## Katana and Batman react to bullets

358 / 114 = 3.14035088

0.242276923 * 3.14035088 = 0.760834548 meters moved for the sword

The submachine guns somewhat resemble an Uzi: http://i.imgur.com/xW4UUVa.png

Uzis are 400 m/s: http://en.wikipedia.org/wiki/Uzi

0.01 / 400 = 2.5e-5 seconds

0.760834548 / 2.5e-5 = 30433.3819 m/s or mach 89.4336651 Katanas are 1.2 kg

KE = 0.5mv^2

0.5 * 1.2 * 30433.3819^2 = 555714440 joules or 0.132818939 tons of TNT equivalent which is small building level

## Katana reacts to more bullets

1.5748 / 6.5 = 0.242276923

610 / 152 = 4.01315789

0.242276923 * 4.01315789 = 0.972295545 meters moved

Uzis are 400 m/s: http://en.wikipedia.org/wiki/Uzi

0.01 / 400 = 2.5e-5 seconds

0.972295545 / 2.5e-5 = 38891.8218 m/s or mach 114.290228

Katanas are 1.2 kg

KE = 0.5mv^2

0.5 * 1.2 * 38891.8218^2 = 907544282 joules or 0.216908289 tons of TNT equivalent which is verging on building level

## Method 2 (Darkanine)

Our rules say if a character moves at a high speed while carrying an object, we can derive the Kinetic Energy of it. So:

Katana weighs 44 kg according to the DC wiki. According to this link, the hand weighs approx 0.5% human body mass, while the arm weighs 4.97%. Can't really tell if she's moving just her hand or arm so I'll use two ends.

0.5% of 44 kg = 0.22 kg

1.2 + 0.22 = 1.42

1.42 * 0.5 * 38891.8218^2 = 1073927400.08 J (Just barely Building level)

4.97% of 44 = 2.1868 kg

1.2 + 2.1868 = 3.3868 kg

3.3868 * 0.5 * 38891.8218^2 = 2561392477.87 J (Still low end Building level)

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