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(Blog post created or updated.)
 
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==Introduction==
 
==Introduction==
Continuing on from my powerscaling of Dwayne McDuffie's Superman, this time we take a look at Justice League of [[File:Justice_League_of_America_Vol_2_30.jpg|thumb|left]]America (2006) Issue #30, "Welcome to Sundown Town, Chapter 3: New Moon Rising", in which Superman destroys a replica of the moon by flying through it at near light speed using special relativity to his aid, much like the Flash's Infinite Mass Punch. This moon was said to be travelling at 7,614,000 km/h by John Stewart or 2,115,000 m/s, this is 6,166.18076 times faster than the speed of sound and 0.705488061% the speed of light. Now there is a lot of controversy surrounding the mass of the moon as Batman stated in the story that it weighed as much as our moon, 81 billion tons. However, this value is off by a billion. Haters like to use this to downplay the feat but Dwayne McDuffie, having a degree in physics attempted to calculate the mass of the moon himself and arrived at that number due to his maths being incorrect, he stated this on his website which has since been deleted. What it was meant to say is that the moon weighs 81 quintillion tons. 
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Continui[[File:Justice_League_of_America_Vol_2_30.jpg|thumb|left|230px]]ng on from my powerscaling of Dwayne McDuffie's Superman, this time we take a look at Justice League of America (2006) Issue #30, "Welcome to Sundown Town, Chapter 3: New Moon Rising", in which Superman destroys a replica of the moon by flying through it at near light speed using special relativity to his aid, much like the Flash's Infinite Mass Punch. This moon was said to be travelling at 7,614,000 km/h by John Stewart or 2,115,000 m/s, this is 6,166.18076 times faster than the speed of sound and 0.705488061% the speed of light. Now there is a lot of controversy surrounding the mass of the moon as Batman stated in the story that it weighed as much as our moon, 81 billion tons. However, this value is off by a billion. Haters like to use this to downplay the feat but Dwayne McDuffie, having a degree in physics attempted to calculate the mass of the moon himself and arrived at that number due to his maths being incorrect, he stated this on his website which has since been deleted. What it was meant to say is that the moon weighs 81 quintillion tons. 
 
==Attack Potency==
 
==Attack Potency==
In order to completrely stop the moon in its tracks and destroy it, Superman would need to exert an amount of energy equal to the kinetic energy of the moon added to the gravitational binding energy of the moon. The gravitational binding energy of the moon is equal to: '''3G(mass of the moon)<sup>2</sup>/5(radius of the moon) = 1.24434983×10<sup>29</sup> J (29.7406747 petatons of TNT) - Moon level (naturally)'''
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[[File:Shadow_moon_speed.jpg|thumb|162px]]In order to completrely stop the moon in its tracks and destroy it, Superman would need to exert an amount of energy equal to the kinetic energy of the moon added to the gravitational binding energy of the moon. The gravitational binding energy of the moon is equal to: '''3G(mass of the moon)<sup>2</sup>/5(radius of the moon) = 1.24434983×10<sup>29</sup> J (29.7406747 petatons of TNT) - Moon level (naturally)'''
   
 
Now for the kinetic energy of the moon: '''0.5(mass of the moon)(2,115,000)<sup>2 </sup>= 1.64338975×10<sup>35</sup> J (39.2779577 yottatons of TNT) - Large Planet level'''
 
Now for the kinetic energy of the moon: '''0.5(mass of the moon)(2,115,000)<sup>2 </sup>= 1.64338975×10<sup>35</sup> J (39.2779577 yottatons of TNT) - Large Planet level'''
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Now adding the two together: '''1.24434983×10<sup>29</sup>+1.64338975×10<sup>35 </sup>= 1.64339099×10<sup>35</sup> J (39.2779874 yottatons of TNT) - Large Planet level (still)'''
 
Now adding the two together: '''1.24434983×10<sup>29</sup>+1.64338975×10<sup>35 </sup>= 1.64339099×10<sup>35</sup> J (39.2779874 yottatons of TNT) - Large Planet level (still)'''
 
==Speed==
 
==Speed==
Now this next part people aren't going to like as kinetic energy calculations using FTL values are disallowed here, but for those of you who are interested I will be calculating the speed that Superman COULD have reached to attain the same kinetic energy had relativity not been by his side. 
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[[File:Shadow_moon_2.jpg|thumb|238px]]Now this next part people aren't going to like as kinetic energy calculations using FTL values are disallowed here, but for those of you who are interested I will be calculating the speed that Superman COULD have reached to attain the same kinetic energy had relativity not been by his side. 
   
 
Superman's mass according to https://dc.fandom.com/wiki/Kal-El_(New_Earth) is 225 lb which is 102.058 kg. Therefore rearranging the kinetic energy equation for speed we get: '''[2(1.64339099×10<sup>35</sup>)/102.058]<sup>1/2 </sup>= 5.67494059×10<sup>16</sup> m/s = 189,295,642× FTL (~189 million) - MFTL+'''
 
Superman's mass according to https://dc.fandom.com/wiki/Kal-El_(New_Earth) is 225 lb which is 102.058 kg. Therefore rearranging the kinetic energy equation for speed we get: '''[2(1.64339099×10<sup>35</sup>)/102.058]<sup>1/2 </sup>= 5.67494059×10<sup>16</sup> m/s = 189,295,642× FTL (~189 million) - MFTL+'''

Latest revision as of 00:52, 20 September 2019

Introduction

Continui

Justice League of America Vol 2 30

ng on from my powerscaling of Dwayne McDuffie's Superman, this time we take a look at Justice League of America (2006) Issue #30, "Welcome to Sundown Town, Chapter 3: New Moon Rising", in which Superman destroys a replica of the moon by flying through it at near light speed using special relativity to his aid, much like the Flash's Infinite Mass Punch. This moon was said to be travelling at 7,614,000 km/h by John Stewart or 2,115,000 m/s, this is 6,166.18076 times faster than the speed of sound and 0.705488061% the speed of light. Now there is a lot of controversy surrounding the mass of the moon as Batman stated in the story that it weighed as much as our moon, 81 billion tons. However, this value is off by a billion. Haters like to use this to downplay the feat but Dwayne McDuffie, having a degree in physics attempted to calculate the mass of the moon himself and arrived at that number due to his maths being incorrect, he stated this on his website which has since been deleted. What it was meant to say is that the moon weighs 81 quintillion tons. 

Attack Potency

Shadow moon speed

In order to completrely stop the moon in its tracks and destroy it, Superman would need to exert an amount of energy equal to the kinetic energy of the moon added to the gravitational binding energy of the moon. The gravitational binding energy of the moon is equal to: 3G(mass of the moon)2/5(radius of the moon) = 1.24434983×1029 J (29.7406747 petatons of TNT) - Moon level (naturally)

Now for the kinetic energy of the moon: 0.5(mass of the moon)(2,115,000)= 1.64338975×1035 J (39.2779577 yottatons of TNT) - Large Planet level

Now adding the two together: 1.24434983×1029+1.64338975×1035 = 1.64339099×1035 J (39.2779874 yottatons of TNT) - Large Planet level (still)

Speed

Shadow moon 2

Now this next part people aren't going to like as kinetic energy calculations using FTL values are disallowed here, but for those of you who are interested I will be calculating the speed that Superman COULD have reached to attain the same kinetic energy had relativity not been by his side. 

Superman's mass according to https://dc.fandom.com/wiki/Kal-El_(New_Earth) is 225 lb which is 102.058 kg. Therefore rearranging the kinetic energy equation for speed we get: [2(1.64339099×1035)/102.058]1/2 = 5.67494059×1016 m/s = 189,295,642× FTL (~189 million) - MFTL+

In my previous calculation I calculated his speed under the same writer to be anywhere between 1.9 million to a billion times the speed of light and this value falls within that range and so in my opinion should be accepted. Here's a link to that: https://vsbattles.fandom.com/wiki/User_blog:ComicBookMyths/ComicBookMyths_Calculation_No._1:_%22Superman_covers_light-years_in_a_short_amount_of_time.%22

Strength

And now for the interesting part, the relatavistic mass that Superman was pulling with him in order to destroy the moon below light speed. Firstly, his actual speed is so close to the speed of light that there's no point trying to calculate it and so for all intents and purposes we will just assume that his speed is equal to the speed of light, this will just slightly lowball the mass he had behind him.

All we have to do is rearrange the equation for mass while assuming he is travelling at light speed: 2(1.64339099×1035)/c2 = 3.65703816×1018 kg' ('4.03119453×1015 tons)' - Class P'. Equal to the mass of small moons or asteroids and according to https://en.wikipedia.org/wiki/Orders_of_magnitude_(mass)#cite_note-134 it is almost the mass of Earth's atmosphere.

Acceleration

If we take the energy value and divide by the impact distance which in this case is the diamater of the moon we can get a force value, and if we divide this by our recently calculated mass we can get an acceleration value like so:

1.64339099×1035/(diamater of moon) = 4.72945491×1028 N

4.72945491×1028/3.65703816×1018 = 1.29324735×1010 m/s2 (1.31874529×10gs)