based on the narutoforums calc.
Scaling[]
Height of the clouds = 2000 meters
Size of the hole:
Angle = 2 * atan(tan(70/2)*(177/545)) = 25.623146363074 degrees
Distance = 2000 meters
Size = 909.63 meters
So the diameter of the hole thing in which Jellal forms his meteor is 909.63 meters
Hole Diameter = 909.63 meters = 209 px
Meteorite Diameter = 86 px = 86( 909.63/209) = 374.29 meters
(4/3)pi*(374.29/2)^3 = 27455116.738 m^3
Meteor Density = 3350 kg/m^3
27455116.738 * 3350 = 91974641072.3 kg
Calculation[]
Low-End(Ablation Speed, 2000 m/s):
KE= 0.5(91974641072.3)2000^2 = 183949282144600000 joules = 43.9 megatons (7-B)
Mid-End(Atmopsheric Entry Speed, 11200 m/s):
KE= 0.5(91974641072.3)11200^2 = 5768649488054656000joules = 1.37 gigatons (High 7-A)
The Low.End assumes that the meteor was created somwhere in the clouds, and simply ablated.
The Mid-End assumes that the meteor was summoned/dragged from beyond the atmopshere