VS Battles Wiki

We have moved to a new external forum hosted at https://vsbattles.com

For information regarding the procedure that needs to be exactly followed to register there, please click here.

READ MORE

VS Battles Wiki
Register
Advertisement
VS Battles Wiki
Screenshot (422)

Ring of Destruction - Slamming People through the Stage[]

You can do that, even through steel, which is what I will be calculating.

  • Biggest character in this game is Jumbo Jack, who has a surface area of 32700 cm^2 (Average of all the results), cut that in half is 16350 cm^2.
  • Since the hole made is just a generic human shape I'll use average pro wrestler height to pixel scale the depth of the hole, which seems to be roughly 6'1 or 185.4 cm.
  • 185.4 / 483.58 * 126 = 48.30 cm
  • 48.30 * 16350 = 789705 cm^3
  • Gonna have three ends for destruction, personally I think at least VFrag is justified since the fighter goes through cleanly. There's a pretty big cloud of dust even on stages that don't really have anything that should produce dust too so you could argue pulv.
    • Frag: 208 * 789705 = 164258640 Joules, Small Building level
    • VFrag: 568.5 * 789705 = 448947292.5 Joules, Small Building level
    • Pulv: 655 * 789705 = 517256775 Joules, Small Building level+
  • This can also be used for lifting strength. There's a lot of weird wrestling throws so I'm just gonna use full height as the distance of the force.
    • 164258640 / 1.854 / 9.81 = 9031283.71 kg - 9000+ tons, Class M
    • 448947292.5 / 1.854 / 9.81 = 24684061.49 kg - 24000+ tons, Class M
    • 517256775 / 1.854 / 9.81 = 28439859.76 kg - 28000+, Class M
  • El KLOL LS
    • 16350 * 655 / 9.81 = 1091666.66 kg, Class M
17 abigail01cvarf

Street Fighter V - Bolshoi Russian Suplex[]

One of Zangief's moves shoves the opponent halfway through the ground, which can even happen to the huge Abigail (weirdly loud video), who is 244 cm.

  • Will calc the area of Abigail's shoulders as they pierced the ground. Note that for their depth I'll use Abigail's arms since they're roughly as thick. Also I'll calc it as a rectangle since it's pretty rectangle-y and ignores the fact that the bands would have increased the thickness a bit more.
  • 244 / 571 * 132.06 = 56.43 cm
  • 244 / 571 * 371 = 158.53 cm
  • 244 / 571 * 265 = 113.23 cm, but I'm actually going to have to split the feat in two, since there are stages with a metallic (iron?) floor, which I will assume to be 10 cm thick because... idk, sounds nice, rest will be reinforced concrete.
  • 103.23 * 158.53 * 56.43 = 923479.87 cm^3. 10 * 158.53 * 56.43 = 89458.48 cm^3
  • Again, I think there's a good argument for vfrag since the destruction would have to be huge to let Abigail through without being vfrag, but I'll let the evaluator decide.
    • Frag: (89458.48 * 20) + (923479.87 * 10) = 11023968.3 Joules, Wall level+
    • Vfrag: (89458.48 * 42.43) + (923479.87 * 61.2) = 60312691.35 Joules, Small Building level
  • Now, LS. Suplexes are weird so I'll use Zangief's height (213.36 cm) as the distance of force, could be way lower since he seems to apply the force after the suplex itself is done, but idk.
    • Frag: 11023968.3 / 2.1336 / 9.81 = 526691.05 kg, Class K
    • Vfrag: 60312691.35 / 2.1336 / 9.81 = 2881553.57 kg, Class M
  • New KLOL end: 244 / 571 * 216.78 = 92.63
  • 82.63 * 158.53 * 56.43 = 739195.41 cm^3. 10 * 158.53 * 56.43 = 89458.48 cm^3
    • Frag: (89458.48 * 20) + (739195.41 * 10) = 9181123.7 Joules, Wall level
      • LS: 9181123.7 / 0.9263 / 9.81 = 1010357.72 kg, Class M
    • Vfrag: (89458.48 * 42.43) + (739195.41 * 61.2) = 49034482.39 Joules, Small Building level
      • LS: 49034482.39 / 0.9263 / 9.81 = 5396111.61 kg, Class M

Street Fighter Alpha II - That one Akuma feat, again[]

Recalculation of this, with some fixes. My issue with it is that it uses the biggest mountain and assumes that has base mountain height which is kinda weird. So, let's try another method. Given by the name (Goutentou) and Akuma and Ryu both being Japanese, let's assume the island is in Japan.

  • Average mountain in JP seems to be roughly 1600 meters. On the original calc, the middle mountain is 62 px. Instead of doing the calc again, let's get the ratio and upscale the previous result.
  • 1600 / 62 * 84 = 2167.74 m
  • 2167.74 / 609.6 = 3.556x
  • 3.556^3 x 1.615854462 x 10^14 = 7.2658679 x 10^15
  • And that's it for volume, however while the original calculation uses fragmentation, I will also include a violent fragmentation end since the fragments that pass by Ryu are very tiny. Also, younger Japanese mountains (given how sharp these ones look, they should be in that camp) are made out of volcanic rocks, and the most common volcanic rock is Basalt, from a quick search, so I'll use those.
    • Fragmentation: 7.2658679 x 10^15 x 20 = 1.4531736 x 10^17 Joules, City level
    • VFragmentation: 7.2658679 x 10^15 x 130 = 9.4456283 x 10^17 Joules, Mountain level

nice support, unfortunately no tier 6.

Screenshot (423)

Street Fighter III 2nd Impact - That one other Akuma feat, again[]

Same blog. We do splitting feats in a different way now, so.

  • Ayers rock is 3600 m wide and 348 tall, which gives us an area of 1252800 m^2.
  • 3600 / 963 * 5 = 18.69 m
  • Pulverization of sandstone, couldn't find anything for arkose (or arkosic sandstone) which is what Ayers Rock is actually made of but eh, 's alright, is 144.7
  • 144.7 MpA x 18.69 m x 1252800 m^2 = 3.38812619 × 10^15 Joules, High 7-C. Let's try something else.
  • Since there's smoke and the hole is orange-hot and even glows a bit in the middle, I'm gonna calc melting it, I think that's a reasonable assumption.
  • Weight of mass affected (kg) * temperature change (C) * specific capacity of material.
  • Density is 2.5 g/cc. 1869 * 360000 * 34800 * 2.5 = 5.853708 x 10^13 g or 58537080000 kg
  • Arkose was found half-melted at 1150° so let's use that. In the Australian equivalent of a spring night, Ayers Rock is 7-8°, will do 7.5, so temperature change is 1142.5°
  • Specific heat capacity of sandstone is 920.
  • 920 * 58537080000 * 1142.5 = 6.1528325 x 10^16, 7-B. Still useless.
Screenshot (424)

Street Fighter III 3rd Strike - Gill parts the sea[]

Have I mentioned I hate Street Fighter game titles? Feat here, doesn't scale to physicals. Gonna calc the KE of it all moving.

  • Average depth of the Mediterranean sea is 1500 meters
  • Split width = 150000 / 230.67 * 373.22 = 242697.35
  • Split length (Angsizing the back bit of the sea wall) = 150000 * 1080/[25*2*tan(70deg/2)] = 4627199.54 cm.
  • 4627199.54 * 150000 * 242697.35 = 1.6845136 x 10^17 cm^3. Salt water is 1.025 g/cm^3 so 1.7266264 x 10^17 g or 172662640000 metric tons, Class T
  • Speed of the split is half the width and takes... roughly two and a half seconds? I tried frame counting but since the water is always animated I'm unclear when it stops.
  • (2426.9735 / 2) / 2.5 = 485.39 m/s
  • 1.7266264 x 10^14 kg x 0.5 x 485.39^2 = 2.0339957 x 10^19 Joules, Island level
Screenshot (425)

Street Fighter 4 - Zangief hugs a tree[]

Feat here.

Assuming head to body ratio is 1/8 here (which it might not be but I couldn't for the life of me find a half decent pic of Zangief standing straight, dude's always hunching or posing), 213.36 / 8 = 26.67 cm

  • 26.67 / 354 * 1098 = 82.72
  • 26.67 / 354 * 393 = 29.61
  • 56922 * 10 (seems to be a roughly average vfrag rating for wood) = 569220 Joules.
  • Will use radius as the distance of force since that's how much he would have moved.
  • 569220 / 0.148 / 9.81 = 392057.19 kg, Class K
  • EDIT: Will use pulv instead as suggested by KLOL. American Sycamore, cause its vfrag is roughly 10 j/cc which is what I previously used.
  • 569220 * 37.09 / 0.148 / 9.81 = 14541401.36 kg, Class M
Advertisement