I hate calculating Wall level feats. I'm absolutely sick of them. So I figured, why not calc every Tier 9 feat ever?  You may see no point in calculating wall level feats, but Wall level is an annoyingly wide tier for how low it is. As someone who has calculated many 9-B feats in the past, I can testify that. One 9-B can be hundreds of times stronger than another. It makes all the difference in a matchup to now exactly how strong your character, as is the case with Cuphead vs The Knight, or Pre-Training Saitama vs Baldi. Many of these feats I will be calcing are practically tropes throughout fiction. Feats like busting through walls, getting hit by vehicles, or falling great distances, are all very common. All of those, and more, will be covered in this blog. 

Getting hit by vehicles

Anywho, it's common in cartoons (and fiction in general) to have characters survive getting hit by cars, so I'll run some quick calcs. I will be interchanging the mass to represent different vehicles, and I will be interchanging the velocity to represent different speed limits based on different locations. 

The KE formula will be used for all of these, of course.

KE = 1/2 Mass * Velocity^2

25 mph

When your car is driving through a neighborhood or something like that, the speed limit is most likely going to be 25 mph, or 11.176 m/s. So let's assume different vehicle masses for that.

The average car is about 1,500 kg

0.5(1500) * 11.176^2 = 93,677.232 joules, or 94 Kilojoules - Wall level

Pickup trucks can weigh over 4082.3 kg.

0.5(4082.3) * 11.176^2 = 254,945.709462 joules, or 255 Kilojoules - Wall level

Next up we'll try a school bus. According to wikipedia, a bus can have a curb weight varying from 4,536 kg to 16,329 kg. Obviously your average school bus is going to be much more massive than your average pickup truck, but I don't want to go out of my way with the high end either.

After looking up some stuff, I've found that the "traditional" school bus, AKA Type C, is around 10,659.421 kg (scroll to the bottom page and you'll find a chart).

0.5(10,659.421) * 11.176^2 = 665,696.702668 joules, or 666 Kilojoules - Wall level

Now let's try a semi truck. It's unlikely that you'll find one of these just riding through your neighborhood, but perhaps a cartoon verse would use it as a gag. So let's include it anyway.

Semi trucks can have a mass of 36,000 kg.

0.5(36,000) * 11.176^2 = 2,248,253.568 joules, or 2.24 Megajoules - Wall level

45 mph

When you drive through a town, you know the ones with all of the restaurants and stores everywhere? Odds are the speed limit is 45 mph, or 20.1168 m/s. Something like that.

For an average car:

0.5(1500) * 20.1168^2 = 303,514.23168 joules, or 303 Kilojoules - Wall level

For a pickup truck:

0.5(4082.3) * 20.1168^2 = 826,024.098658 joules, or 826 Kilojoules - Wall level

For a bus:

0.5(10,659.421) * 20.1168^2 = 2,156,857.31665 joules, or 2.15 Megajoules - Wall level

For a semi truck:

0.5(36,000) * 20.1168^2 = 7,284,341.56032 joules, or 7.3 Megajoules - Wall level

60 mph

When you're on the interstate, you're gonna have to be going at least 60 mph, or 26.8224 m/s to keep up with the other cars and not get run over.


0.5(1500) * 26.8224^2 = 539,580.85632 joules, or 529 Kilojoules - Wall level


0.5(4082.3) * 26.8224^2 = 1,468,487.2865 joules, or 1.5 Megajoules - Wall level


0.5(10,659.421) * 26.8224^2 = 3,834,413.00737 joules, or 4 Megajoules - Wall level


0.5(36,000) * 26.8224^2 = 12,949,940.5517 joules, or 13 Megajoules - Wall level+

Believe me, I was pretty disappointed to first find out that land vehicles couldn't even reach 9-A as well.

Human Kinetic Energy

Falling Great Heights

It's a very common feat within fiction for characters to survive falling from heights that absolutely should have killed them. Here, I will be running a series of Kinetic Energy calcs for falling under different conditions. For all of these, I will use the average human for the mass, which is 70 kg. For the first handful of them I will be using this calculator. The peak speed one can reach when below the stratosphere is 53.5 m/s according to the calculator. So anything above that height that is below the stratosphere is going to have that same falling velocity, and thus the same result. I'll do it later though.

KE = 0.5(Mass) * Velocity^2

Throwing People

Specific Wall-Busting Feats

A Human-Shaped Hole 

A common gag you'll find in cartoons is that someone gets slammed into a wall so hard that it leaves a crater shaped like their body. For example, this feat.

This calc will serve as a reference for every time something like that happens in fiction, provided that the character's body is the size of an average human. If they're considerably smaller or bigger, just assume an appropriate value to multiply or divide it by.

So, the average human body has a surface area of 1.9 m^2. Divide that in half and you get 0.95m^2, or 9,500 cm^2.

Going by this, I will assume that the average human head's length (meaning, front to back) is 7/8ths of the average human head's height (23.9 cm), then I will use that for the depth of the crater. 

7/8ths of 23.9 is 20.9125.

20.9125 * 9,500 = 198,668.75 cm^3.

For fragmentation (8 j/cm^3):

198,668.75 * 8 = 1,589,350 joules, or 1.6 Megajoules - Wall level

For violent fragmentation (69 j/cm^3):

198,668.75 * 69 = 13,708,143.75 joules, or 14 Megajoules - Wall level+

Assuming the wall is steel:


198,668.75 * 208 = 41,323,100 joules, or 0.009 Tons of TNT - Small Building level


198,668.75 * 568.5 = 112,943,184 joules, or 0.027 Tons of TNTSmall Building level

Crater with human height as the diameter

Feats like this are pretty straightforward. But I'll do this later.

Digging Up From Underground

This one is more specific and it's referring to a feat Ryukama requested for me. 

The monster in this feat bursts up through the concrete from underground. For this I will assume the volume of the concrete destroyed is a cylinder, using the character's height for... the height, and the shoulder span as the diameter.

The average human height is about 175 cm.

The average human shoulder width is about 18 inches, but I'll bump that up to 24 inches because the measurement only comes from measuring deltoid to deltoid. So about 61 cm, 30.5 for the radius.

So the volume is 5.11e+5 cubic centimeters.


5.11e+5 * 8 = 4,088,000 joules, or 4 Megajoules - Wall level


5.11e+5 * 69 = 35,259,000 joules, or 0.008 Tons of TNT - Small Building level

Assuming the volume is steel:


5.11e+5 * 208 = 106,288,000 joules, or 0.025 Tons of TNT - Small Building level


5.11e+5 * 568.5 = 290,503,500 joules, or 0.069 Tons of TNT - Small Building level

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