## FANDOM

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To calc this feat, I will use the formula for force of shearing, where shear force = area sheared x shear stress, shear stress being the tensile strength of the material x 0.6 (the modification factor for steels).

We'll use steel as the material for the spaceship (however, because this UFO apparently went into warp drive, it is likely something far stronger).

I will assume Juliet is as tall as the average US white woman i.e. 164.9 cm

Image 1:

Juliet = 1.649m = 76 pixels

Height of relevant parts of UFO = 300 pixels = 6.509 m

Length of middle section of UFO = 490 pixels = 10.632m

Length of UFO (min) = 1920 pixels = 41.659m

Image 2:

This is a visualization of how I got the area using the above conditions.

Outer area length = length of UFO - middle section length = 31.027m

Area of middle section = (10.632m)(6.509m)=69.204m^2

Area of outer triangles = (31.027m)(6.509m) = 201.963m^2

Total area = 271.167 m^2

We'll use the lowest tensile strength for steel (400 MPa):

Shear force = (0.6)(400x10^6 N/m^2)(271.167m^2)=6.508x10^10 Newtons

The force it was applied over was at least the height of the middle section since it was a downward slash so:

Work = (6.508x10^10 N)(6.509m) = 4.236x10^11 Joules

Give me some time to account for the area inside the spacecraft, however.

Edit: Apparently it was a near completely solid aircraft with a space at the top and bottom....welp