Kai Splits a Mountain[]
In this scene, Kai slams into the ground so hard, it splits the mountain behind it. We don't see Kai in the image, if we did it would've been a lot easier to find the size of the mountain, but instead we see Oogway. Po supposedly is 6'2 or 1.8796 m. In the image, Po is about 371 px while Oogway is about 350 px.
(1.8796/371)*350=1.77320754717 m
Now, in this image, assuming the main portion of the glowing trail is Oogway, that would mean he's about 23 px while the length of the mountain is about 886 px.
(1.77320754717/23)*886=68.3070385562 m
I'll be using shear force to find how much energy he'd need to split the mountain using this method. Using the area of a circle, we get a surface area of:
pi*34.1535192781^2=3664.5512116 m^2
The average MPa of rock is 60 MPa or 60000000 n/m^2. The value to change shear force to tensile is 0.6.
3664.5512116*60000000*.6=131923843618 N
Multiplying it by the diameter now, we get:
131923843618*68.3070385562=9.0113271e+12 J (Small Town level)
Kai Splits Floating Rocks[]
So in the same scene, Kai's attack destroys several other rocks in the spirit realm. We already have a calc for him destroying the two boulders but I'm going to calculate the energy needed to split the other rocks he does in the scene. In total the shockwave splits 4 rocks. 2 in the beginning of the shot and 2 in the other shot. I'll be using the size of the shockwave to scale the latter 2. I'll be using the same method as I used above for the splits.
In this image, Kai is about 25 px tall. The first rock he splits is about 119 px long and the second rock is about 218 px. According to this calc, Kai is about 3.3579 m.
(3.3579/25)*119=15.983604 m
(3.3579/25)*218=29.280888 m
Assuming both rocks are rectangular, that'll mean they both have areas of:
15.983604^2=255.475596829 m^2
29.280888^2=857.370402069 m^2
Once again, MPa of rock is about 60 MPa or 60000000 n/m^2 and the value of shear force is 0.6.
255.475596829*60000000*.6=9197121485.84
857.370402069*60000000*.6=30865334474.5
Multiplying by their lengths:
9197121485.84*15.983604=147003147770 J
30865334474.5*29.280888=903764401830 J
Now as for the other two rocks. In this image, Kai is once again 25 px while the shockwave is 15 px tall.
(3.3579/25)*15=2.01474 m
In this image, the shockwave is 20 px tall while the rock has a width of 469 px and the length that's cut will be 691 px long.
(2.01474/20)*469=47.245653 m
(2.01474/20)*691=69.609267 m
Assuming the width of the rock is comparable to the width of the cut, that gives us an area of:
47.245653*69.609267=3288.73527427 m^2
3288.73527427*60000000*.6*69.609267=8.2413523e+12 J
Now for the final rock, the shockwave in this image is 7 px tall. The rock has a width of 259 px and the cut has a length of 465 px.
(2.01474/7)*259=74.54538 m
(2.01474/7)*465=133.8363 m
That gives us an area of:
74.54538*133.8363=9976.87784129 m^2
9976.87784129*60000000*.6*133.8363=4.8069663e+13 J
Now finally combining all four values plus the original 52 ton value, we get:
2.1825e+11+147003147770+903764401830+8.2413523e+12+4.8069663e+13=5.7580033e+13 J (Town level)