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Pet Shop makes a big chunk of ice via freezing the air, calcing the theoretical energy needed to do that.

302px = 5.194m (Cadillac el Dorado 10th gen from the looks of it, it's a long boy so using the higher end of 5194mm length).

277px = 4.7640331125827816178581m (Icicle Length).

78px = 1.3414966887417218525278m (0.6707483443708609262639 Radius) (Icicle Width Averaged).

Treating it as a cone gets 2.2445m3.

## Air Freezing

Air is 20% Oxygen

Oxygen Volume = (2.2445 Meters^3)*(0.2) = 0.4489 Meters^3

Density of Solid Oxygen = 1426 Kg/Meters^3

Oxygen Mass = (0.4489 Meters^3)*(1426 Kg/Meters^3) = 640.1314 Kg

Q1 = (Oxygen Mass)*(Specific Heat)*(Change in Temperature)

Specific Heat of Oxygen = 918 Joules/Kg Kelvin

Standard Material Temperature = 20 Degrees Celsius = 293.15 Kelvin

Boiling Temperature of Oxygen = 90.2 Kelvin

(640.1314 Kg)*(918 Joules/Kg Kelvin)*(293.15 Kelvin-90.2 Kelvin) = 119261664.88434 Joules

Q2 = (Oxygen Mass)*(Vaporization of Oxygen)

Heat of Vaporization for Oxygen is 214000 Joules/Kg

(640.1314 Kg)*(214000 Joules/Kg) = 136988119.6 Joules

Q3 = (Oxygen Mass)*(Specific Heat)*(Change in Temperature)

Specific Heat of Oxygen = 918 Joules/Kg Kelvin

Boiling Temperature of Oxygen = 90.2 Kelvin

Melting Temperature of Oxygen is 54.75 Kelvin

(640.1314 Kg)*(918 Joules/Kg Kelvin)*(90.2 Kelvin-54.75 Kelvin) = 20831860.16334 Joules

Q4 = (Oxygen Mass)*(Fusion Energy of Oxygen)

Fusion Energy of Oxygen is 13875 Joules/Kg

(640.1314 Kg)*(13875 Joules/Kg) = 8881823.175 Joules

Total Freezing Oxygen Energy = 119261664.88434 + 136988119.6 + 20831860.16334 + 8881823.175 = 285963467.82268 joules.

## Oxygen Freezing

Air is 80% Oxygen

Nitrogen Volume = (2.2445 Meters^3)*(0.8) = 1.7956 Meters^3

Density of Frozen Nitrogen = 1026.5 Kg/Meters^3

Nitrogen Mass = (1.7956 Meters^3)*(1026.5 Kg/Meters^3) = 1843.1834 Kg

Q1 = (Nitrogen Mass)*(Specific Heat)*(Change in Temperature)

Specific Heat of Nitrogen = 1040 Joules/Kg Kelvin

Standard Material Temperature = 20 Degrees Celsius = 293.15 Kelvin

Boiling Temperature of Nitrogen = 77.36 Kelvin

(1843.1834 Kg)*(1040 Joules/Kg Kelvin)*(293.15 Kelvin-77.36 Kelvin) = 413650167.72144 Joules

Q2 = (Nitrogen Mass)*(Vaporization of Nitrogen)

Heat of Vaporization for Nitrogen is 199000 Joules/Kg

(1843.1834 Kg)*(199000 Joules/Kg) = 366793496.6 Joules

Q3 = (Nitrogen Mass)*(Specific Heat)*(Change in Temperature)

Specific Heat of Nitrogen = 1040 Joules/Kg Kelvin

Boiling Temperature of Nitrogen = 77.36 Kelvin

Melting Temperature of Nitrogen is 63.15 Kelvin

(1843.1834 Kg)*(1040 Joules/Kg Kelvin)*(77.36 Kelvin-63.15 Kelvin) = 27239301.55856 Joules

Q4 = (Nitrogen Mass)*(Fusion Energy of Nitrogen)

Fusion Energy of Nitrogen is 25800 Joules/Kg

(1843.1834 Kg)*(25800 Joules/Kg) = 47554131.72 Joules

Total Freezing Nitrogen Energy = 413650167.72144 + 366793496.6 + 27239301.55856 + 47554131.72 = 855237097.6 joules.

## End Result

Total Energy: 285963467.82268 + 855237097.6 = 1141200565.42268 joules, 0.27 tons, 8-C.